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Chemische vergelijkingen in evenwicht op03/17/25

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Breng de vergelijking van een chemische reactie in evenwicht
Fe(ClO3)2 + C3AlN3 = C2FeN2 + Al(ClO3)3 =>
3 Fe(ClO3)2 + 2 C3AlN3 = 3 C2FeN2 + 2 Al(ClO3)3

Zn(NO3)2(aq) + H2SO4(aq) = ZnSO4(s) + HNO3(aq) =>
Zn(NO3)2(aq) + H2SO4(aq) = ZnSO4(s) + 2 HNO3(aq)

C4H9OH + NaBr + H2SO4 = C4H9Br + H2O + Na2SO4 =>
2 C4H9OH + 2 NaBr + H2SO4 = 2 C4H9Br + 2 H2O + Na2SO4

CH2O + H2S = H2O + C3H6S3 =>
3 CH2O + 3 H2S = 3 H2O + C3H6S3

Cd(NO3)2 + NaCl = NaNO3 + CdCl2 =>
Cd(NO3)2 + 2 NaCl = 2 NaNO3 + CdCl2

SO4{2-}(aq) + H{+}(aq) + Br{-}(aq) = Br2(aq) + SO2(g) + H2O(l) =>
SO4{2-}(aq) + 4 H{+}(aq) + 2 Br{-}(aq) = Br2(aq) + SO2(g) + 2 H2O(l)

NaOH(ac) + H2O(l) + Al(s) = NaAlO2(ac) + H2(g) =>
2 NaOH(ac) + 2 H2O(l) + 2 Al(s) = 2 NaAlO2(ac) + 3 H2(g)

Be + H3PO4 = Be3(PO4)2 + P2O3 + H2O =>
6 Be + 10 H3PO4 = 2 Be3(PO4)2 + 3 P2O3 + 15 H2O

CN + O = CNO =>
CN + O = CNO

C2H6 + CO = CH3CH2CHO =>
C2H6 + CO = CH3CH2CHO

C2H8N4 + O2 = CO2 + H2O + NO2 =>
C2H8N4 + 8 O2 = 2 CO2 + 4 H2O + 4 NO2

(CH3)2CHOH + H2SO4 + KMnO4 = (CH3)2CO + K2SO4 + MnSO4 + H2O =>
5(CH3)2CHOH + 3 H2SO4 + 2 KMnO4 = 5(CH3)2CO + K2SO4 + 2 MnSO4 + 8 H2O

C17H19NO3 + H2O = C17H20NO3{+} + OH{-} =>
C17H19NO3 + H2O = C17H20NO3{+} + OH{-}

CuO + CH3COOH = Cu(C2H3O2)2 + H + O =>
CuO + 2 CH3COOH = Cu(C2H3O2)2 + 2 H + O

NaAl(Si2O6) = Na + Al + Si + O =>
NaAl(Si2O6) = Na + Al + 2 Si + 6 O

C6H5NH2 + CH3Cl = C6H5NHCH3 + HCl =>
C6H5NH2 + CH3Cl = C6H5NHCH3 + HCl

H2O + P4 + KOH = PH3 + KH2PO2 =>
3 H2O + P4 + 3 KOH = PH3 + 3 KH2PO2

CaC2H3O2 + NaC2 = CaC2 + NaC2H3O2 =>
CaC2H3O2 + NaC2 = CaC2 + NaC2H3O2

Na3PO4 + KOH = NaOH + K3PO4 =>
Na3PO4 + 3 KOH = 3 NaOH + K3PO4

NaOH + HClO4 = H2O + NaClO4 =>
NaOH + HClO4 = H2O + NaClO4

Ca(subscript)3(PO(subscript)4)(subscript)2 + SiO(subscript)2 = P(subscript)4O(subscript)10 + CaSiO(subscript)3 =>
2 Ca(subscript)3(PO(subscript)4)(subscript)2 + 6 SiO(subscript)2 = P(subscript)4O(subscript)10 + 6 CaSiO(subscript)3

HBr + HCl + Ba(OH)2 = BaBrCl + H2O =>
HBr + HCl + Ba(OH)2 = BaBrCl + 2 H2O

K2CrO4 + (NH4)(ClO3) = (NH4)2(CrO4) + K(ClO3) =>
K2CrO4 + 2(NH4)(ClO3) = (NH4)2(CrO4) + 2 K(ClO3)

NaOH + K2HPO4 = KOH + Na2HPO4 =>
2 NaOH + K2HPO4 = 2 KOH + Na2HPO4

Fe2O3 + C = C2O4 + Fe =>
4 Fe2O3 + 6 C = 3 C2O4 + 8 Fe

NH2OH + Fe(SO4)3 = N2 + Fe(OH)2 + H2SO4 + H2O =>
4 NH2OH + Fe(SO4)3 = 2 N2 + Fe(OH)2 + 3 H2SO4 + 2 H2O

Cr2O3 + OH = OHCrO4 + H2O =>
Cr2O3 + 12 OH = 2 OHCrO4 + 5 H2O

FeCl2 + K2(CO3) = FeCO3 + KCl =>
FeCl2 + K2(CO3) = FeCO3 + 2 KCl

HCl2 + Cu = CuCl2 + H =>
HCl2 + Cu = CuCl2 + H

NaOH*5H2O + CuSO4 = CuO + Na2SO4 + H2O =>
2 NaOH*5H2O + CuSO4 = CuO + Na2SO4 + 11 H2O

CuFe2S3 + H2O + O = CuFeS2 + H2SO3 + Fe =>
CuFe2S3 + H2O + 2 O = CuFeS2 + H2SO3 + Fe

CaCl + NaCO3 = CaCO3 + Na2Cl2 =>
2 CaCl + 2 NaCO3 = 2 CaCO3 + Na2Cl2

COCl2 + CH3OH = H3COCOOCH3 + HCl =>
COCl2 + 2 CH3OH = H3COCOOCH3 + 2 HCl

Ca(HO)2 + (HCl) = CaCl2 + H2O =>
Ca(HO)2 + 2(HCl) = CaCl2 + 2 H2O

I + (HNO3)10 = (HIO3)2 + (NO2)10 + (H2O)4 =>
2 I + (HNO3)10 = (HIO3)2 + (NO2)10 + (H2O)4

Nb5 + O2 = NbO =>
2 Nb5 + 5 O2 = 10 NbO

C3H8 + O = H2O + CO6 =>
C3H8 + 22 O = 4 H2O + 3 CO6

Cu{2+} + NH2OH{+} = N2O + H2O + Cu{+} + H{+} =>
2 Cu{2+} + 2 NH2OH{+} = N2O + H2O + 2 Cu{+} + 4 H{+}

(Hg)2(C2H3O2)2(aq) + KCl(aq) = (Hg)2Cl2(s) + KC2H3O2(aq) =>
(Hg)2(C2H3O2)2(aq) + 2 KCl(aq) = (Hg)2Cl2(s) + 2 KC2H3O2(aq)

Ba(OH)2 + CrO2Cl2 = BaCrO4 + BaCl2 + H2O =>
2 Ba(OH)2 + CrO2Cl2 = BaCrO4 + BaCl2 + 2 H2O

H2SO4 = H2 + SO4 =>
H2SO4 = H2 + SO4

K2C2O4 + FeCl3 = FeK3(C2O4)3 + KCl =>
3 K2C2O4 + FeCl3 = FeK3(C2O4)3 + 3 KCl

CH3COOH + MgCO3 = Mg(CH3COOH)2 + CO2 + H2O =>
9 CH3COOH + 4 MgCO3 = 4 Mg(CH3COOH)2 + 6 CO2 + 2 H2O

MnO2 + HCl = MnCl2 + H2O + Cl2 =>
MnO2 + 4 HCl = MnCl2 + 2 H2O + Cl2

Cd + CuCl2 = CdCl2 + Cu =>
Cd + CuCl2 = CdCl2 + Cu

Fe + NaCl + O2 + H2O = FeCl2 + NaOH =>
2 Fe + 4 NaCl + O2 + 2 H2O = 2 FeCl2 + 4 NaOH

Mn2 + NaBiO3 + HNO3 = HMnO4 + BiONO3 + NaNO3 + H2O =>
Mn2 + 7 NaBiO3 + 14 HNO3 = 2 HMnO4 + 7 BiONO3 + 7 NaNO3 + 6 H2O

Rb + Al2O3 = Rb2O + Al =>
6 Rb + Al2O3 = 3 Rb2O + 2 Al

MnSO4 + NaCO3 = MnCO3 + NaSO4 =>
MnSO4 + NaCO3 = MnCO3 + NaSO4

O + HCl2 + NaH3 = NaCl3 + H2O =>
9 O + 6 HCl2 + 4 NaH3 = 4 NaCl3 + 9 H2O

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Breng de vergelijking van een chemische reactie in evenwicht
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