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Chemische vergelijkingen in evenwicht op01/30/25

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Breng de vergelijking van een chemische reactie in evenwicht
C2H5OH + O2 = COH + H2O =>
2 C2H5OH + 3 O2 = 4 COH + 4 H2O

Na3(PO4) + CaCO3 = Na2CO3 + Ca3(PO4)2 =>
2 Na3(PO4) + 3 CaCO3 = 3 Na2CO3 + Ca3(PO4)2

NaClO + NH4Cl = NaCl + N2 + H2O + Cl2 =>
4 NaClO + 2 NH4Cl = 4 NaCl + N2 + 4 H2O + Cl2

CaCl2 + H2CO3 = Ca(CO3) + HCl =>
CaCl2 + H2CO3 = Ca(CO3) + 2 HCl

CH2O2 + C2H5OH = CH3COOC2H5 + H2O =>
2 CH2O2 + 3 C2H5OH = 2 CH3COOC2H5 + 3 H2O

H2OCrO3 + CH3C6H4NO2 = C7H5NO4 + CrO + H2O =>
3 H2OCrO3 + 2 CH3C6H4NO2 = 2 C7H5NO4 + 3 CrO + 5 H2O

(NH4)2(SO4) + AgNO3 = (NH4)NO3 + Ag2(SO4) =>
(NH4)2(SO4) + 2 AgNO3 = 2(NH4)NO3 + Ag2(SO4)

C3H2O2 + O2 = H2O + CO2 =>
2 C3H2O2 + 5 O2 = 2 H2O + 6 CO2

OC6H12O6(s) + O2(g) = CO2(g) + H2O(g) =>
2 OC6H12O6(s) + 11 O2(g) = 12 CO2(g) + 12 H2O(g)

PbNO3 + HI = PbI + HNO3 =>
PbNO3 + HI = PbI + HNO3

Br + O2 = Br2O3 =>
4 Br + 3 O2 = 2 Br2O3

H2SO4(aq) + NaOH(aq) = H2O(l) + Na2SO4(aq) =>
H2SO4(aq) + 2 NaOH(aq) = 2 H2O(l) + Na2SO4(aq)

Li2O + SO3 = Li2(SO4) =>
Li2O + SO3 = Li2(SO4)

Na2SiO4 + BaCl2 = NaCl + BaSiO4 =>
Na2SiO4 + BaCl2 = 2 NaCl + BaSiO4

C2H5OH + Mn2O7 = H2O + CH3COOH + MnO2 =>
3 C2H5OH + 2 Mn2O7 = 3 H2O + 3 CH3COOH + 4 MnO2

C6H5C2H3 + KMnO4 + H2O = C6H5C2H3(OH)2 + KOH + MnO2 =>
3 C6H5C2H3 + 2 KMnO4 + 4 H2O = 3 C6H5C2H3(OH)2 + 2 KOH + 2 MnO2

AgNO3 + F = NO3 + AgF =>
AgNO3 + F = NO3 + AgF

K + HNO3 = KNO3 + N2 + H2O =>
10 K + 12 HNO3 = 10 KNO3 + N2 + 6 H2O

Ba(NO3)3 + Na2SO4 = Ba2(SO4)3 + NaNO3 =>
2 Ba(NO3)3 + 3 Na2SO4 = Ba2(SO4)3 + 6 NaNO3

KAl(OH)4 + BaCl2 = Ba(OH)2 + KAlCl4 =>
KAl(OH)4 + 2 BaCl2 = 2 Ba(OH)2 + KAlCl4

BaCl2 + Sn(SO4)2 = BaSO4 + SnCl4 =>
2 BaCl2 + Sn(SO4)2 = 2 BaSO4 + SnCl4

Ca(OH)2 + H(NO3) = H(OH) + Ca(NO3)2 =>
Ca(OH)2 + 2 H(NO3) = 2 H(OH) + Ca(NO3)2

SO4 + Ca2H = CaSO4 + H2 =>
4 SO4 + 2 Ca2H = 4 CaSO4 + H2

VOCl3 + H2O = VO2Cl + HCl =>
VOCl3 + H2O = VO2Cl + 2 HCl

H2O2 + CaCl2 + NH3 + H2O = CaO2(H2O)5 + NH4Cl =>
H2O2 + CaCl2 + 2 NH3 + 5 H2O = CaO2(H2O)5 + 2 NH4Cl

FeCl2(aq) + NH3(aq) = FeNH(s) + HCl =>
FeCl2(aq) + NH3(aq) = FeNH(s) + 2 HCl

HCl + LiCN = HCN + ClLi =>
HCl + LiCN = HCN + ClLi

K = K12 =>
12 K = K12

Fe3O4 + HCl*8H2O = FeCl2 + FeCl3 + H2O =>
Fe3O4 + 8.0000000000001HCl*8H2O = FeCl2 + 2 FeCl3 + 68.000000000001H2O

AgCH3COO + Co(II)Br = AgBr + Co(II)CH3COO =>
AgCH3COO + Co(II)Br = AgBr + Co(II)CH3COO

FeCl3(aq) + AgNO3(aq) = AgCl3(s) + Fe(NO3)(aq) =>
FeCl3(aq) + AgNO3(aq) = AgCl3(s) + Fe(NO3)(aq)

Hg(NH4)SbO4 + Au2Cl6 = Au2Hg6Sb6O24 + HCl + NH3 =>
6 Hg(NH4)SbO4 + Au2Cl6 = Au2Hg6Sb6O24 + 6 HCl + 6 NH3

HClO3 + Pb(OH)4 = Pb(ClO3)4 + H2O =>
4 HClO3 + Pb(OH)4 = Pb(ClO3)4 + 4 H2O

Co(NO3)2*6H2O + NaHCO3 + H2O2 = Na3[Co(CO3)3] + H2O + NaNO3 + CO2 =>
2 Co(NO3)2*6H2O + 10 NaHCO3 + H2O2 = 2 Na3[Co(CO3)3] + 18 H2O + 4 NaNO3 + 4 CO2

SiO2 + HF = SiF4 + H2O =>
SiO2 + 4 HF = SiF4 + 2 H2O

Hg(NO3)2 + NH4OH = Hg2NH2NO3 + H2O + NH4NO3 =>
8 Hg(NO3)2 + 18 NH4OH = 4 Hg2NH2NO3 + 15 H2O + 13 NH4NO3

KMnO4 + HCl + CH3OH = MnCl2 + HCOOH + KCl + H2O =>
4 KMnO4 + 12 HCl + 5 CH3OH = 4 MnCl2 + 5 HCOOH + 4 KCl + 11 H2O

KMnO4 + ZnSO3 + H2SO4 = MnSO4 + K2SO4 + ZnSO4 + H2O =>
2 KMnO4 + 5 ZnSO3 + 3 H2SO4 = 2 MnSO4 + K2SO4 + 5 ZnSO4 + 3 H2O

H2O = H2 + O =>
H2O = H2 + O

Na2S2O3 + I3 = Na{+} + I{-} + S4O6 =>
6 Na2S2O3 + 4 I3 = 12 Na{+} + 12 I{-} + 3 S4O6

C6H12O + KMnO4 + H2SO4 = C6H10O4 + K2SO4 + MnSO4 + H2O =>
5 C6H12O + 8 KMnO4 + 12 H2SO4 = 5 C6H10O4 + 4 K2SO4 + 8 MnSO4 + 17 H2O

CaHPO4 + C6H10O5 = Ca(C6H11PO9) =>
CaHPO4 + C6H10O5 = Ca(C6H11PO9)

CH2OHCHNH2COOH + O2 = NO3{-} + H{+} + H2O + CO2 =>
2 CH2OHCHNH2COOH + 9 O2 = 2 NO3{-} + 2 H{+} + 6 H2O + 6 CO2

Ca3(PO4)2 + H2SO4 = CaSO4 + Ca(H2PO4)2 =>
Ca3(PO4)2 + 2 H2SO4 = 2 CaSO4 + Ca(H2PO4)2

(CH3)2CO + Ca(OCl)2 = CHCl3 + Ca(CH3COO)2 + Ca(OH)2 =>
2(CH3)2CO + 3 Ca(OCl)2 = 2 CHCl3 + Ca(CH3COO)2 + 2 Ca(OH)2

MgF2 + Na2S = MgS + NaF =>
MgF2 + Na2S = MgS + 2 NaF

HC2H3O2 + Cu = CuC2H3O2 + H2 =>
2 HC2H3O2 + 2 Cu = 2 CuC2H3O2 + H2

NiCl2(s) + O2(g) = NiO2(s) + Cl2O5(g) =>
2 NiCl2(s) + 7 O2(g) = 2 NiO2(s) + 2 Cl2O5(g)

Co(Cl2)(s) + O2(g) = Co(ClO3)2(s) =>
Co(Cl2)(s) + 3 O2(g) = Co(ClO3)2(s)

Al + HB4O7 = Al2(B4O7)3 + H2 =>
4 Al + 6 HB4O7 = 2 Al2(B4O7)3 + 3 H2

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Breng de vergelijking van een chemische reactie in evenwicht
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