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Chemische vergelijkingen in evenwicht op01/10/25

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Breng de vergelijking van een chemische reactie in evenwicht
CH3COOH + CH3CH3CHCH2COHCH3 = CH3COOCHCH3CH2CHCH3CH3 + H2O =>
8 CH3COOH + 12 CH3CH3CHCH2COHCH3 = 11 CH3COOCHCH3CH2CHCH3CH3 + 6 H2O

C3H7I + I2 = C3H6I2 + HI =>
C3H7I + I2 = C3H6I2 + HI

CuSO4 + NaOH = Cu(OH)2 + Na2SO4 =>
CuSO4 + 2 NaOH = Cu(OH)2 + Na2SO4

C6H8O6 + NaHCO3 = C6H7NaO6 + CO2 + H2O =>
C6H8O6 + NaHCO3 = C6H7NaO6 + CO2 + H2O

Cl2 + K3AsO3 + KOH = KCl + H2O + K3AsO4 =>
Cl2 + K3AsO3 + 2 KOH = 2 KCl + H2O + K3AsO4

KOH + NaOH = H2O + KNaO =>
KOH + NaOH = H2O + KNaO

HCIO + NaOH = NaCIO + HOH =>
HCIO + NaOH = NaCIO + HOH

Tc2(CO3)7 + Cd(ClO2)2 = Tc(ClO2)7 + CdCO3 =>
Tc2(CO3)7 + 7 Cd(ClO2)2 = 2 Tc(ClO2)7 + 7 CdCO3

KMnO4 + SO2 + H2O = H2SO4 + K2SO4 + MnSO4 =>
2 KMnO4 + 5 SO2 + 2 H2O = 2 H2SO4 + K2SO4 + 2 MnSO4

CH3Cl = C2H6 + Cl2 =>
2 CH3Cl = C2H6 + Cl2

KI + NaNO2 + H2SO4 = I2 + NO + KHSO4 + NaHSO4 + H2O =>
2 KI + 2 NaNO2 + 4 H2SO4 = I2 + 2 NO + 2 KHSO4 + 2 NaHSO4 + 2 H2O

SnO2(s) + Sn(s) + H2SO4(aq) = SnSO4(s) + H2O(l) =>
SnO2(s) + Sn(s) + 2 H2SO4(aq) = 2 SnSO4(s) + 2 H2O(l)

Fe + HCl = FeCl2 + H2 =>
Fe + 2 HCl = FeCl2 + H2

H3PO4 + (NH4)2MoO4 + HNO2 = (NH4)3PO4*12MoO3 + NH4NO3 + H2O =>
2 H3PO4 + 24(NH4)2MoO4 + 84 HNO2 = 2(NH4)3PO4*12MoO3 + 63 NH4NO3 + 3 H2O

K2Cr2O7 + HCl + C2H5OH = CrCl + CO2 + KCl + H2O =>
6 K2Cr2O7 + 24 HCl + 5 C2H5OH = 12 CrCl + 10 CO2 + 12 KCl + 27 H2O

Cu2S + HNO3 = Cu(NO3)2 + S + H2O + N2O3 =>
Cu2S + 6 HNO3 = 2 Cu(NO3)2 + S + 3 H2O + N2O3

H3 + PO4 + Fe(OH)2 = FePO4 + H2O =>
2 H3 + 3 PO4 + 3 Fe(OH)2 = 3 FePO4 + 6 H2O

AgCl + NO3H = AgNO3 + HCl =>
AgCl + NO3H = AgNO3 + HCl

KI + NaClO = NaCl + K2O + I2 =>
2 KI + NaClO = NaCl + K2O + I2

MgOH + H2O = MgH2 + OH =>
MgOH + 2 H2O = MgH2 + 3 OH

C4H9OH + CuO = C3H7CHO + H2O + Cu =>
C4H9OH + CuO = C3H7CHO + H2O + Cu

Co2(SO4)3 + HCl = CoCl2 + Cl2 + H2SO4 =>
Co2(SO4)3 + 6 HCl = 2 CoCl2 + Cl2 + 3 H2SO4

HF + K2SO4 = H2SO4 + KF =>
2 HF + K2SO4 = H2SO4 + 2 KF

KMnO4 + Na2SO3 + KOH = K2MnO4 + H2O + Na2SO4 =>
2 KMnO4 + Na2SO3 + 2 KOH = 2 K2MnO4 + H2O + Na2SO4

Mg(NO3)2 + Mn(NO3)2 + Fe(NO3)3 + SC(NH2)2 + Na2S = MgMnFe2S9 + NaO + H2O + CO2 + N2 =>
Mg(NO3)2 + Mn(NO3)2 + 2 Fe(NO3)3 + 6 SC(NH2)2 + 3 Na2S = MgMnFe2S9 + 6 NaO + 12 H2O + 6 CO2 + 11 N2

H2SO4 + KClO2 = HClO2 + K2SO4 =>
H2SO4 + 2 KClO2 = 2 HClO2 + K2SO4

C10H18O + C3Cl3N3O3 = C10H16O + C3H3N3O3 + Cl =>
3 C10H18O + 2 C3Cl3N3O3 = 3 C10H16O + 2 C3H3N3O3 + 6 Cl

AlSO4 + BaCl2 = AlCl3 + Ba + SO4 =>
2 AlSO4 + 3 BaCl2 = 2 AlCl3 + 3 Ba + 2 SO4

Ca + F2 = CaF2 =>
Ca + F2 = CaF2

NaMnO4 + Na2SO3 + H2O = Na2SO4 + NaOH + MnO2 =>
2 NaMnO4 + 3 Na2SO3 + H2O = 3 Na2SO4 + 2 NaOH + 2 MnO2

AlSO4 + BaCl2 = AlCl3 + Ba + SO4 =>
2 AlSO4 + 3 BaCl2 = 2 AlCl3 + 3 Ba + 2 SO4

Cu(SO4) + Na(OH) = Cu(OH)2 + Na2(SO4) =>
Cu(SO4) + 2 Na(OH) = Cu(OH)2 + Na2(SO4)

KAl3Si3O10(OH)2 + H2O + H = Al2Si2O5(OH)4 + K =>
2 KAl3Si3O10(OH)2 + 3 H2O + 2 H = 3 Al2Si2O5(OH)4 + 2 K

KIO3 + KI + HCl = KI2 + H2O + KCl =>
KIO3 + 11 KI + 6 HCl = 6 KI2 + 3 H2O + 6 KCl

BCl3 + H2O = H3BO3(aq) + HCl(aq) =>
BCl3 + 3 H2O = H3BO3(aq) + 3 HCl(aq)

F + HCl = FCl2 + H2 =>
F + 2 HCl = FCl2 + H2

Al2S + H2O = Al(OH)3 + H2 + S =>
Al2S + 6 H2O = 2 Al(OH)3 + 3 H2 + S

Sb2(CO3)5 + HCl = SbCl5 + H2O + CO2 =>
Sb2(CO3)5 + 10 HCl = 2 SbCl5 + 5 H2O + 5 CO2

Al(C2H3O2)3 + Cd(NO3)2 = Al(NO3)3 + Cd(C2H3O2)2 =>
2 Al(C2H3O2)3 + 3 Cd(NO3)2 = 2 Al(NO3)3 + 3 Cd(C2H3O2)2

PO4 = P2O5 + O2 =>
4 PO4 = 2 P2O5 + 3 O2

HBr + (NH4)2CO3 = H2CO3 + NH4Br =>
2 HBr + (NH4)2CO3 = H2CO3 + 2 NH4Br

C8H8N2O3 + H2O = C6H6N2O2 + CH3COOH =>
C8H8N2O3 + H2O = C6H6N2O2 + CH3COOH

C + HOH = CO + H2 =>
C + HOH = CO + H2

Fe + H2SO4 = Fe2(SO4)3 + H2 =>
2 Fe + 3 H2SO4 = Fe2(SO4)3 + 3 H2

Na + Pb(No3) = Pb + Na(No3)2 =>
Na + 2 Pb(No3) = 2 Pb + Na(No3)2

MgN2 + H2O = MgO + HN =>
MgN2 + H2O = MgO + 2 HN

NH3 + SO2 + H2O = (NH4)2SO3 =>
2 NH3 + SO2 + H2O = (NH4)2SO3

KMnO4 + FeI2 + H2SO4 = K2SO4 + MnSO4 + Fe2(SO4)3 + I2 + H2O =>
6 KMnO4 + 10 FeI2 + 24 H2SO4 = 3 K2SO4 + 6 MnSO4 + 5 Fe2(SO4)3 + 10 I2 + 24 H2O

HCOONa + CH3Cl = HCOOCH3 + NaCl =>
HCOONa + CH3Cl = HCOOCH3 + NaCl

Ca{2+} + [EDTA]{4-} = Ca[EDTA]{-2} =>
Ca{2+} + [EDTA]{4-} = Ca[EDTA]{-2}

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Breng de vergelijking van een chemische reactie in evenwicht
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