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Chemische vergelijkingen in evenwicht op01/09/25

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Breng de vergelijking van een chemische reactie in evenwicht
HIO3 + K2S + HCl = I2 + S + KCl + H2O =>
2 HIO3 + 5 K2S + 10 HCl = I2 + 5 S + 10 KCl + 6 H2O

NH4Br + Na3PO4 = NH4PO4 + Na3Br =>
NH4Br + Na3PO4 = NH4PO4 + Na3Br

Na3PO4(aq) + AgNO3(aq) = Ag3PO4(s) + NaNO3(aq) =>
Na3PO4(aq) + 3 AgNO3(aq) = Ag3PO4(s) + 3 NaNO3(aq)

NaH + H2O = NaH3O =>
NaH + H2O = NaH3O

HNO2 + Br2 = HBr + NO2 =>
2 HNO2 + Br2 = 2 HBr + 2 NO2

Ca + Cu(NO3)2 = Ca(NO3) + Cu =>
2 Ca + Cu(NO3)2 = 2 Ca(NO3) + Cu

AgNO3 + NaBH4 + H2O = Ag + NaNO3 + H3BO3 + H2 =>
2 AgNO3 + 2 NaBH4 + 6 H2O = 2 Ag + 2 NaNO3 + 2 H3BO3 + 7 H2

NaBr + CaF2 = NaF + CaBr2 =>
2 NaBr + CaF2 = 2 NaF + CaBr2

NH3 + Al = AlN + H2 =>
2 NH3 + 2 Al = 2 AlN + 3 H2

H2SO4 + NaOCl = HOCl + Na2SO4 =>
H2SO4 + 2 NaOCl = 2 HOCl + Na2SO4

CH3COOH + KHS = KCH3COO + H2S =>
CH3COOH + KHS = KCH3COO + H2S

Ca(ClO)2 + H2O = HClO + CaOHOCl =>
Ca(ClO)2 + H2O = HClO + CaOHOCl

NaOCl + HNO3 = NaNO3 + Cl2 + H2O + O2 =>
4 NaOCl + 4 HNO3 = 4 NaNO3 + 2 Cl2 + 2 H2O + O2

NH3 + O2 + CH4 = HCN + H2O =>
2 NH3 + 3 O2 + 2 CH4 = 2 HCN + 6 H2O

Zn + H2O2 = Zn(OH)2 =>
Zn + H2O2 = Zn(OH)2

HCIO4 + K2CO3 = H2CO3 + KCIO4 =>
2 HCIO4 + K2CO3 = H2CO3 + 2 KCIO4

SO2 + H2 = S + H2O =>
SO2 + 2 H2 = S + 2 H2O

CaCl2 + HCl = CaCl + HCl2 =>
CaCl2 + HCl = CaCl + HCl2

Ba + OH + HNO3 = Ba(NO3)2 + H2O =>
Ba + 2 OH + 2 HNO3 = Ba(NO3)2 + 2 H2O

Fe3ClO2 + NH4OH = Fe3OH + NH4ClO2 =>
Fe3ClO2 + NH4OH = Fe3OH + NH4ClO2

Ba(OH)2(ac) + H3PO4(ac) = Ba3(PO4)2 + H2O =>
3 Ba(OH)2(ac) + 2 H3PO4(ac) = Ba3(PO4)2 + 6 H2O

Sn + NaOH + HOH = H2 + Na2(Sn(OH)4) =>
Sn + 2 NaOH + 2 HOH = H2 + Na2(Sn(OH)4)

LiO + HCl = LiCl2 + H2O =>
LiO + 2 HCl = LiCl2 + H2O

NH3(g) + HCl(ac) = NH4Cl =>
NH3(g) + HCl(ac) = NH4Cl

MnO4({-}) + CN({-}) + H2O = MnO2 + OCN({-}) + OH({-}) =>
2 MnO4({-}) + 3 CN({-}) + H2O = 2 MnO2 + 3 OCN({-}) + 2 OH({-})

Na3PO4 + PbSO4 = Na2SO4 + Pb3(PO4)2 =>
2 Na3PO4 + 3 PbSO4 = 3 Na2SO4 + Pb3(PO4)2

C6H12NNaO3S + O2 = CO2 + H2O + Na + N + S =>
2 C6H12NNaO3S + 15 O2 = 12 CO2 + 12 H2O + 2 Na + 2 N + 2 S

Ca(CH3COO)2 + H3PO4 = Ca3(PO4)2 + HCH3COO =>
3 Ca(CH3COO)2 + 2 H3PO4 = Ca3(PO4)2 + 6 HCH3COO

SO2 + C = CSO2 =>
SO2 + C = CSO2

AgNO3 + AlCl3 = AgCl + Al(NO3)3 =>
3 AgNO3 + AlCl3 = 3 AgCl + Al(NO3)3

NaClO2 + Cl = NaCl + ClO2 =>
NaClO2 + Cl = NaCl + ClO2

KNO3 + NH3 = KNO2 + N2 + H2O =>
3 KNO3 + 2 NH3 = 3 KNO2 + N2 + 3 H2O

Ca(CH3COO)2 + KMnO4 = K2MnO4 + CaCO3 + CO2 + H2O + MnO2 =>
Ca(CH3COO)2 + 8 KMnO4 = 4 K2MnO4 + CaCO3 + 3 CO2 + 3 H2O + 4 MnO2

K2[Hg(SCN)4] + CoCl2 = HgCl2 + K2[Co(SCN)4] =>
K2[Hg(SCN)4] + CoCl2 = HgCl2 + K2[Co(SCN)4]

NaClO2 = NaCl + O2 =>
NaClO2 = NaCl + O2

Zn + H2SO4 = ZnSO4 + S + H2O =>
3 Zn + 4 H2SO4 = 3 ZnSO4 + S + 4 H2O

CuO2 + H2O = Cu(OH)4 =>
CuO2 + 2 H2O = Cu(OH)4

CuSCN(s) + KSO4(aq) + NaOH(aq) = Cu(NaOH)SO4(s) + KSCN(aq) =>
CuSCN(s) + KSO4(aq) + NaOH(aq) = Cu(NaOH)SO4(s) + KSCN(aq)

KMnO4 + H2SO4 + SnCl2 = MnSO4 + K2SO4 + SnCl4 + H2O + SnSO4 =>
2 KMnO4 + 8 H2SO4 + 10 SnCl2 = 2 MnSO4 + K2SO4 + 5 SnCl4 + 8 H2O + 5 SnSO4

K2Cr2O7 + NO2 + HNO3 = KNO3 + Cr(NO3)3 + H2O =>
K2Cr2O7 + 6 NO2 + 2 HNO3 = 2 KNO3 + 2 Cr(NO3)3 + H2O

CuSO4 + CO2 = C(SO4)2 + Cu + O2 =>
2 CuSO4 + CO2 = C(SO4)2 + 2 Cu + O2

S + NH3 = S4N4 + H2S =>
10 S + 4 NH3 = S4N4 + 6 H2S

B4H10 + KMnO4 = KBO2 + MnO2 + H2O + KOH =>
3 B4H10 + 22 KMnO4 = 12 KBO2 + 22 MnO2 + 10 H2O + 10 KOH

NaBiO3 + C2H5OH + HCl = BiCl3 + NaCl + CO2 + H2O =>
6 NaBiO3 + C2H5OH + 24 HCl = 6 BiCl3 + 6 NaCl + 2 CO2 + 15 H2O

NaHCO3(aq) + HNO3(aq) = NaNO3 + H2O + CO2 =>
NaHCO3(aq) + HNO3(aq) = NaNO3 + H2O + CO2

PbCr2O7 + NaOH = Pb(OH)2 + Na2CrO4 + H2O =>
PbCr2O7 + 4 NaOH = Pb(OH)2 + 2 Na2CrO4 + H2O

Pb3(PO4)4 + (NH4)2Cr2O7 = (NH4)3PO4 + Pb(Cr2O7)2 =>
Pb3(PO4)4 + 6(NH4)2Cr2O7 = 4(NH4)3PO4 + 3 Pb(Cr2O7)2

C6H5OH + HBr2 = C6H2Br3OH + HBr =>
C6H5OH + 6 HBr2 = C6H2Br3OH + 9 HBr

C3H8O3 = C + H2 + O2 =>
2 C3H8O3 = 6 C + 8 H2 + 3 O2

C2H2O4*2H2O + K2Cr2O7 + K2C2O4*H2O = K3[Cr(C2O4)3]*3H2O + CO2 + H2O =>
7 C2H2O4*2H2O + K2Cr2O7 + 2 K2C2O4*H2O = 2 K3[Cr(C2O4)3]*3H2O + 6 CO2 + 17 H2O

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Breng de vergelijking van een chemische reactie in evenwicht
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