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Chemische vergelijkingen in evenwicht op01/08/25

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Breng de vergelijking van een chemische reactie in evenwicht
Li2CrO4 + AuI3 = LiI + Au2(CrO4)3 =>
3 Li2CrO4 + 2 AuI3 = 6 LiI + Au2(CrO4)3

C2H4 + O2 = C02 + H2O =>
C2H4 + O2 = C02 + 2 H2O

H2S + CrO7{-2} + H{+} = S + Cr{3+} + H2O =>
9 H2S + 2 CrO7{-2} + 10 H{+} = 9 S + 2 Cr{3+} + 14 H2O

KMnO4 + H2SO4 + FeSO4 = K2SO4 + MnSO4 + Fe2(SO4)5 + H2O =>
6 KMnO4 + 24 H2SO4 + 10 FeSO4 = 3 K2SO4 + 6 MnSO4 + 5 Fe2(SO4)5 + 24 H2O

Ba(OH)2 + Al(OH)3 = Ba(AlO2)2 + H2O0 =>
Ba(OH)2 + 2 Al(OH)3 = Ba(AlO2)2 + 4 H2O0

ZnSO4 + NH4OH = (NH4)2SO4 + Zn(OH)2 =>
ZnSO4 + 2 NH4OH = (NH4)2SO4 + Zn(OH)2

MgSO4*7H2O = MgSO4 + H2O =>
MgSO4*7H2O = MgSO4 + 7 H2O

C21H40O2 + O2 = CO2 + H2O =>
C21H40O2 + 30 O2 = 21 CO2 + 20 H2O

Ag2Se + O2 = Ag2O + SeO2 =>
2 Ag2Se + 3 O2 = 2 Ag2O + 2 SeO2

Na2S + F = NaF + S2 =>
2 Na2S + 4 F = 4 NaF + S2

Na4[UO2(CO3)3] + HCl = NaCl + UO2Cl2 + CO2 + H2O =>
Na4[UO2(CO3)3] + 6 HCl = 4 NaCl + UO2Cl2 + 3 CO2 + 3 H2O

KMnO4 + K2SO4 + H2SO4 = MnSO4 + K2S2O8 + H2O =>
2 KMnO4 + 4 K2SO4 + 8 H2SO4 = 2 MnSO4 + 5 K2S2O8 + 8 H2O

C12H17N4OS + K3Fe(CN)6 + KOH = K4Fe(CN)6 + H2O + C12H14N4OS =>
C12H17N4OS + 3 K3Fe(CN)6 + 3 KOH = 3 K4Fe(CN)6 + 3 H2O + C12H14N4OS

H2S(g) + FeHO2(s) = Fe2S3(s) + H2O(g) =>
3 H2S(g) + 2 FeHO2(s) = Fe2S3(s) + 4 H2O(g)

Fe(NO3)3*9H2O + CH4N2O = FeO + CO2 + H2O + N2 =>
6 Fe(NO3)3*9H2O + 16 CH4N2O = 6 FeO + 16 CO2 + 86 H2O + 25 N2

K3[FeF6] + KOH = Fe(OH)3 + KF =>
K3[FeF6] + 3 KOH = Fe(OH)3 + 6 KF

Zn + MnO2 + HCl = ZnCl2 + MnCl + H2O =>
3 Zn + 2 MnO2 + 8 HCl = 3 ZnCl2 + 2 MnCl + 4 H2O

CH3COOH + NaCl = CHCl + NaOH =>
CH3COOH + 2 NaCl = 2 CHCl + 2 NaOH

HN3 + HCl + Au = HAuCl3 + NH4Cl =>
HN3 + 15 HCl + 4 Au = 4 HAuCl3 + 3 NH4Cl

Ba(NO3)2 + Al2(SO4)2 = Al(NO3)2 + BaSO4 =>
2 Ba(NO3)2 + Al2(SO4)2 = 2 Al(NO3)2 + 2 BaSO4

C3H8 + O2N2 = CO2 + H2O + N2 =>
C3H8 + 5 O2N2 = 3 CO2 + 4 H2O + 5 N2

NG4OH + H3PO4 = (NG4)3PO4 + H2O =>
3 NG4OH + H3PO4 = (NG4)3PO4 + 3 H2O

C7H7NO2 + NaI + NaOCl = C7H7NO2I + NaCl + NaO =>
C7H7NO2 + NaI + NaOCl = C7H7NO2I + NaCl + NaO

Mg + Cl2 = MgCl2 =>
Mg + Cl2 = MgCl2

MgO(s) + C(s) + Cl2(g) = MgCl2(l) + CO2(g) =>
2 MgO(s) + C(s) + 2 Cl2(g) = 2 MgCl2(l) + CO2(g)

ZnOHCl + NaOH = Zn(OH)2 + NaCl =>
ZnOHCl + NaOH = Zn(OH)2 + NaCl

C7H7Cl + KOH = K(C7H6Cl) + H2O =>
C7H7Cl + KOH = K(C7H6Cl) + H2O

C6H5CCl3 + C6H5CO2H = C6H5COCl + HCl =>
C6H5CCl3 + C6H5CO2H = 2 C6H5COCl + HCl

Ca5F(PO4)3 + H2SO4 + H2O = (CaSO4*2H2O) + HF + H3PO4 =>
Ca5F(PO4)3 + 5 H2SO4 + 10 H2O = 5(CaSO4*2H2O) + HF + 3 H3PO4

KOH + MgI2 = Mg(OH)2 + KI =>
2 KOH + MgI2 = Mg(OH)2 + 2 KI

BaH2(s) + H2O(l) = Ba(OH)2(ac) + H2(g) =>
BaH2(s) + 2 H2O(l) = Ba(OH)2(ac) + 2 H2(g)

CO + K2CrO4 + H2SO4 = CO2 + Cr2(SO4)3 + K3SO4 + H2O =>
11 CO + 6 K2CrO4 + 13 H2SO4 = 11 CO2 + 3 Cr2(SO4)3 + 4 K3SO4 + 13 H2O

K2Cr2O7 + H2SO4 + Na2SO3 = Cr2(SO4)3 + K2SO4 + Na2SO4 + H2O =>
K2Cr2O7 + 4 H2SO4 + 3 Na2SO3 = Cr2(SO4)3 + K2SO4 + 3 Na2SO4 + 4 H2O

Ba(OH)2 + Al(OH)3 = Ba(AlO2)2 + H2O0 =>
Ba(OH)2 + 2 Al(OH)3 = Ba(AlO2)2 + 4 H2O0

KNO2 + KI + H2O = I2 + NO + KOH =>
2 KNO2 + 2 KI + 2 H2O = I2 + 2 NO + 4 KOH

SO3{2-} + HCl = HSO3{-} + Cl{-} =>
SO3{2-} + HCl = HSO3{-} + Cl{-}

Pt + NaCl = PtCl4 + Na =>
Pt + 4 NaCl = PtCl4 + 4 Na

Re(CO)5Br + Zn + HO2CCH3 = ReH(CO)5 + ZnBrO2CCH3 =>
Re(CO)5Br + Zn + HO2CCH3 = ReH(CO)5 + ZnBrO2CCH3

K2O + HNO3 = H2O + KNO3 =>
K2O + 2 HNO3 = H2O + 2 KNO3

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

Ba(OH)2 + Al + H2O = Ba(Al(OH)4)2 + H2 =>
Ba(OH)2 + 2 Al + 6 H2O = Ba(Al(OH)4)2 + 3 H2

Mg + Cl2 = MgCl2 =>
Mg + Cl2 = MgCl2

AuO(OH) + H3PO4 = AuPO4 + H2O =>
AuO(OH) + H3PO4 = AuPO4 + 2 H2O

CuS + NO3{-} + H{+} = Cu2{+} + (SO4)2{-} + NO + H2O =>
6 CuS + 16 NO3{-} + 16 H{+} = 3 Cu2{+} + 3(SO4)2{-} + 16 NO + 8 H2O

LiOH(aq) + HClO3(aq) = LiClO3(aq) + H2O =>
LiOH(aq) + HClO3(aq) = LiClO3(aq) + H2O

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O

(NH4)3PO4 + CuClO3 = (NH4)3ClO3 + CuPO4 =>
(NH4)3PO4 + CuClO3 = (NH4)3ClO3 + CuPO4

Fe(OH)3 + Cu = CuO + Fe + H2O =>
2 Fe(OH)3 + 3 Cu = 3 CuO + 2 Fe + 3 H2O

Ti + NaOH = TiOH + Na =>
Ti + NaOH = TiOH + Na

Fe + NO = Fe2O3 + N2 =>
4 Fe + 6 NO = 2 Fe2O3 + 3 N2

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Breng de vergelijking van een chemische reactie in evenwicht
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