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Chemische vergelijkingen in evenwicht op12/23/24

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Breng de vergelijking van een chemische reactie in evenwicht
BaO(s) + C(s) = BaC2(s) + CO(g) =>
BaO(s) + 3 C(s) = BaC2(s) + CO(g)

MnO2 + NaCl = MnCl2 + NaO =>
MnO2 + 2 NaCl = MnCl2 + 2 NaO

NH3 = N + H3 =>
NH3 = N + H3

Pb(NO3)2(aq) + NaSo4(aq) = Pb(So4)2(aq) + NaNO3(aq) =>
Pb(NO3)2(aq) + 2 NaSo4(aq) = Pb(So4)2(aq) + 2 NaNO3(aq)

C2090H4159O3011N5241 + O2 + Cl = CO2 + H2O + Cl2ONO3 =>
4 C2090H4159O3011N5241 + 48425 O2 + 41928 Cl = 8360 CO2 + 8318 H2O + 20964 Cl2ONO3

ZnCO3 + H2SO4 = ZnSO4H2O + CO2 =>
ZnCO3 + H2SO4 = ZnSO4H2O + CO2

NaZnO2 + H2O = Zn(OH)2 + NaO =>
NaZnO2 + H2O = Zn(OH)2 + NaO

Mn2{+} + [BiO3]{-} + H{+} = [MnO4]{-} + Bi3{+} + H2O =>
14 Mn2{+} + 39[BiO3]{-} + 10 H{+} = 28[MnO4]{-} + 13 Bi3{+} + 5 H2O

Al2(SO4)3 + NH3 = Al(OH)3 + NO3 + S =>
Al2(SO4)3 + 2 NH3 = 2 Al(OH)3 + 2 NO3 + 3 S

KMnO4 + H2SO4 + H2C2O4 = CO2 + H2O + K2SO4 + MnSO4 =>
2 KMnO4 + 3 H2SO4 + 5 H2C2O4 = 10 CO2 + 8 H2O + K2SO4 + 2 MnSO4

Br2 + KOH + Cl2 = KCl + KBrO3 + H2O =>
Br2 + 12 KOH + 5 Cl2 = 10 KCl + 2 KBrO3 + 6 H2O

SO3(g) + Ba(OH)2(aq) = BaSO4(aq) + H2O(l) =>
SO3(g) + Ba(OH)2(aq) = BaSO4(aq) + H2O(l)

Sr + FBr = SrBr2 + F2 =>
Sr + 2 FBr = SrBr2 + F2

Mg + FeSO4 = Fe + Mg(SO4)3 =>
Mg + 3 FeSO4 = 3 Fe + Mg(SO4)3

Cr2O3 + KMnO4 + H2SO4 = K2SO4 + MnSO4 + H2O + Cr2O5 =>
5 Cr2O3 + 4 KMnO4 + 6 H2SO4 = 2 K2SO4 + 4 MnSO4 + 6 H2O + 5 Cr2O5

Zr + O = ZrO2 =>
Zr + 2 O = ZrO2

C4H6 + KMnO4 + H2O = C4H9O3 + MnO2 + KOH =>
C4H6 + KMnO4 + 2 H2O = C4H9O3 + MnO2 + KOH

Zn + Fe(SO4)3 = ZnSO4 + Fe =>
3 Zn + Fe(SO4)3 = 3 ZnSO4 + Fe

C9H12 + HNO3 = C9H6O6 + H2O + N2 =>
5 C9H12 + 18 HNO3 = 5 C9H6O6 + 24 H2O + 9 N2

CH14O06 + H2 = C14H30 + H2O =>
14 CH14O06 + H2 = C14H30 + 84.000000000001H2O

Fe3O4 + H2SO4 = Fe2(SO4)3 + S + H2O =>
6 Fe3O4 + 28 H2SO4 = 9 Fe2(SO4)3 + S + 28 H2O

Na2SO3(s) + HCl(aq) = H2O(l) + SO2(g) + NaCl(aq) =>
Na2SO3(s) + 2 HCl(aq) = H2O(l) + SO2(g) + 2 NaCl(aq)

AlP + H2O = Al2O3 + H3P =>
2 AlP + 3 H2O = Al2O3 + 2 H3P

H2TeO4 + Li(OH) = Li2TeO4 + H2O =>
H2TeO4 + 2 Li(OH) = Li2TeO4 + 2 H2O

Mg(ClO3)2 + Pb = Pb(ClO3)3 + Mg =>
3 Mg(ClO3)2 + 2 Pb = 2 Pb(ClO3)3 + 3 Mg

C10H15NO + I = C10H15N + OI =>
C10H15NO + I = C10H15N + OI

Sr(NO3)2 + Al(NO3)3 + *Eu(NO3)3 + *Dy(NO3)3 + (NH2)2CO = Sr97Al2O4*Eu1Dy2 + H2O + CO2 + NO2 =>
679 Sr(NO3)2 + 14 Al(NO3)3 + 7*Eu(NO3)3 + 14*Dy(NO3)3 + 205(NH2)2CO = 7 Sr97Al2O4*Eu1Dy2 + 410 H2O + 205 CO2 + 1873 NO2

C6H8O7 + NH2 = C6H17N3O7 + C6H6O7 =>
5 C6H8O7 + 6 NH2 = 2 C6H17N3O7 + 3 C6H6O7

Al(NO3)3 + Na2SO3 + H2O = Al(OH)3 + NaNO3 + H2SO3 =>
2 Al(NO3)3 + 3 Na2SO3 + 6 H2O = 2 Al(OH)3 + 6 NaNO3 + 3 H2SO3

NH3 + Cl = NH4Cl + N2 =>
8 NH3 + 6 Cl = 6 NH4Cl + N2

P2O5 + Pb(NO3)2 = Pb3(PO4)2 + N2O5 =>
P2O5 + 3 Pb(NO3)2 = Pb3(PO4)2 + 3 N2O5

(COOH)2 + NaOH = NaCO2 + H2O =>
(COOH)2 + 2 NaOH = 2 NaCO2 + 2 H2O

Cu(NO3)2 + Na2CrO7 = NaNO3 + CuCrO7 =>
Cu(NO3)2 + Na2CrO7 = 2 NaNO3 + CuCrO7

KMnO4 + H2O2 = O2 + MnO2 + KOH =>
2 KMnO4 + H2O2 = 2 O2 + 2 MnO2 + 2 KOH

C9H12 + HNO3 = C9H6O6 + H2O + N2 =>
5 C9H12 + 18 HNO3 = 5 C9H6O6 + 24 H2O + 9 N2

KMnO4 + H2O + Ba(NO2)2 = Ba(NO3)2 + KOH + MnO2 =>
4 KMnO4 + 2 H2O + 3 Ba(NO2)2 = 3 Ba(NO3)2 + 4 KOH + 4 MnO2

MoCl3 + NH4OH = Mo(NH3)6Cl3 + H2O =>
MoCl3 + 6 NH4OH = Mo(NH3)6Cl3 + 6 H2O

KClO3 = KCl + O =>
KClO3 = KCl + 3 O

C9H12 + HNO3 = C9H6O6 + H2O + N2 =>
5 C9H12 + 18 HNO3 = 5 C9H6O6 + 24 H2O + 9 N2

CaCl2(aq) + NaNO3(aq) = CaNO3(aq) + NaCl2(aq) =>
CaCl2(aq) + NaNO3(aq) = CaNO3(aq) + NaCl2(aq)

KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2

CrCl3 + NaI = CrI3 + NaCl =>
CrCl3 + 3 NaI = CrI3 + 3 NaCl

KClO3 + P4 = P4O10 + KCl =>
10 KClO3 + 3 P4 = 3 P4O10 + 10 KCl

Pb(NO3)2 + AgCl = PbCl2 + AgNO3 =>
Pb(NO3)2 + 2 AgCl = PbCl2 + 2 AgNO3

C2H9SH + O2 = CO2 + H2O + SO2 =>
2 C2H9SH + 11 O2 = 4 CO2 + 10 H2O + 2 SO2

C9H12 + HNO3 = C9H6O6 + H2O + N2 =>
5 C9H12 + 18 HNO3 = 5 C9H6O6 + 24 H2O + 9 N2

NH4Al(SO4)2 + NaOH = NH4OH + Al(OH)3 + Na2SO4 =>
NH4Al(SO4)2 + 4 NaOH = NH4OH + Al(OH)3 + 2 Na2SO4

C9H12 + HNO3 = C9H6O6 + H2O + N2 =>
5 C9H12 + 18 HNO3 = 5 C9H6O6 + 24 H2O + 9 N2

KCl + CaS = KS + CaCl =>
KCl + CaS = KS + CaCl

(NH4)2CrO4 + Ba(OH)2 = NH4OH + BaCrO4 =>
(NH4)2CrO4 + Ba(OH)2 = 2 NH4OH + BaCrO4

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Breng de vergelijking van een chemische reactie in evenwicht
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