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Chemische vergelijkingen in evenwicht op12/14/24

 Vergelijkingen in evenwicht op de vorige dag 
Breng de vergelijking van een chemische reactie in evenwicht
C6H12O6 + H2SO4 = CO2 + H2O + S2 =>
C6H12O6 + 4 H2SO4 = 6 CO2 + 10 H2O + 2 S2

Mg(s)H2O(g) = MgO(s)H2(g) =>
Mg(s)H2O(g) = MgO(s)H2(g)

Sr(OH)2 + H2(SO4) = H(OH) + Sr(SO4) =>
Sr(OH)2 + H2(SO4) = 2 H(OH) + Sr(SO4)

Zn + C10H16N2O8 = Zn(C10H16N2O8) =>
Zn + C10H16N2O8 = Zn(C10H16N2O8)

H(ClO3) + HCl = H2O + Cl2 =>
H(ClO3) + 5 HCl = 3 H2O + 3 Cl2

Sr(OH)2 + H2(SO4) = H(OH) + Sr(SO4) =>
Sr(OH)2 + H2(SO4) = 2 H(OH) + Sr(SO4)

Ba + CrO4 = Ba(CrO4) =>
Ba + CrO4 = Ba(CrO4)

I{-} + SO4{-2} + H{+} = I2 + H2S + H2O =>
8 I{-} + SO4{-2} + 10 H{+} = 4 I2 + H2S + 4 H2O

CO(NH2)2HN3 = HN3CO(NH2)2 =>
CO(NH2)2HN3 = HN3CO(NH2)2

P4(s) + Cl2(g) = PCl5(g) =>
P4(s) + 10 Cl2(g) = 4 PCl5(g)

Ca(OH)2 + Ag3PO4 = Ca3(PO4)2 + AgOH =>
3 Ca(OH)2 + 2 Ag3PO4 = Ca3(PO4)2 + 6 AgOH

Mg(OH)2 + Ca(OH)2 = CaMg + OH =>
Mg(OH)2 + Ca(OH)2 = CaMg + 4 OH

HBr + Mg(OH)2 = MgBr2 + H2O =>
2 HBr + Mg(OH)2 = MgBr2 + 2 H2O

CH3CH2CH = CH2 =>
CH3CH2CH = 3 CH2

C2HC + O2 = CO2 + H2O =>
4 C2HC + 13 O2 = 12 CO2 + 2 H2O

Mg(s)H2O(g) = MgOH2 =>
Mg(s)H2O(g) = MgOH2

B + O2 = BO =>
2 B + O2 = 2 BO

MnO4{-2} + H2SO3 = Mn{+2} + SO4{-2} + H2O =>
MnO4{-2} + 2 H2SO3 = Mn{+2} + 2 SO4{-2} + 2 H2O

H1000C350 + O2 + Uuo90 = CO2 + H2OUuo90 =>
H1000C350 + 600 O2 + 500 Uuo90 = 350 CO2 + 500 H2OUuo90

Cu(OH)2 + Mg = Mg(OH)2 + Cu =>
Cu(OH)2 + Mg = Mg(OH)2 + Cu

NH4I + Cl2 = NH4Cl + I2 =>
2 NH4I + Cl2 = 2 NH4Cl + I2

HCl(r) + O2(r) = H2O(r) + Cl2O =>
2 HCl(r) + O2(r) = H2O(r) + Cl2O

Mg + Ca(NO3)2 = Ca + Mg(NO3)2 =>
Mg + Ca(NO3)2 = Ca + Mg(NO3)2

Rb3PO4 + NiCl2 = RbCl + Ni3(PO4)2 =>
2 Rb3PO4 + 3 NiCl2 = 6 RbCl + Ni3(PO4)2

Mg(OH)2 + C20H14O4 = MgC20H16O6 =>
Mg(OH)2 + C20H14O4 = MgC20H16O6

Li2CrO4 + H2SO4 = Li2SO4 + H2CrO4 =>
Li2CrO4 + H2SO4 = Li2SO4 + H2CrO4

CH4 + CaSO4 = CaCO3 + H2O + H2S =>
CH4 + CaSO4 = CaCO3 + H2O + H2S

KNO3 + BaCl2 = KCl + Ba(NO3)2 =>
2 KNO3 + BaCl2 = 2 KCl + Ba(NO3)2

CH3POCl2 + HNC(CH3)N(C2H5)2 + (C2H5)3N = CH3P(O)(Cl)NC(CH3)N(C2H5)2 + (C2H5)3N*HCl =>
CH3POCl2 + HNC(CH3)N(C2H5)2 + (C2H5)3N = CH3P(O)(Cl)NC(CH3)N(C2H5)2 + (C2H5)3N*HCl

FeSO3 + Na2SO4 + H2O = Fe2(SO4)3 + SO2 + NaOH =>
2 FeSO3 + 4 Na2SO4 + 4 H2O = Fe2(SO4)3 + 3 SO2 + 8 NaOH

CH3CH(OH)CH3 + K2Cr2O7 + H3PO4 = CH3CH(O)CH3 + CrPO4 + K3PO4 + H2O =>
18 CH3CH(OH)CH3 + 3 K2Cr2O7 + 8 H3PO4 = 18 CH3CH(O)CH3 + 6 CrPO4 + 2 K3PO4 + 21 H2O

H2SO4 + BrK = Br2 + K2SO4 + SO2 + H2O =>
2 H2SO4 + 2 BrK = Br2 + K2SO4 + SO2 + 2 H2O

CH3C(O)OH + NaOH = CH3C(O)ONa + H2O =>
CH3C(O)OH + NaOH = CH3C(O)ONa + H2O

BaO + NaHCO3 = Ba(HCO3)2 + Na2O =>
BaO + 2 NaHCO3 = Ba(HCO3)2 + Na2O

MnCl5 + K3P = Mn3P5 + KCl =>
3 MnCl5 + 5 K3P = Mn3P5 + 15 KCl

SnCl2 + Ba(OH)2 = Sn(OH)4 + ClBa =>
SnCl2 + 2 Ba(OH)2 = Sn(OH)4 + 2 ClBa

CH3CH2OOCH2CH3 + NaOH = CH3CH2OONa + CH3CH2OH =>
CH3CH2OOCH2CH3 + NaOH = CH3CH2OONa + CH3CH2OH

HCl + Mn02 = H02 + MnCl2 =>
4 HCl + Mn02 = 2 H02 + 2 MnCl2

NaCl + Zn(NO3)2 = Na(NO3) + ZnCl2 =>
2 NaCl + Zn(NO3)2 = 2 Na(NO3) + ZnCl2

NaClO + NH3 = NaCl + NH + H2O =>
NaClO + NH3 = NaCl + NH + H2O

AuO2 + H = Au3 + H2O =>
3 AuO2 + 12 H = Au3 + 6 H2O

O2 + KI + H2SO4 = I2 + K2SO4 + H2O =>
O2 + 4 KI + 2 H2SO4 = 2 I2 + 2 K2SO4 + 2 H2O

Cr2O7{2-} + CH3CHO + H{+} = Cr3{+} + CH3COOH + H2O =>
3 Cr2O7{2-} + 17 CH3CHO + 8 H{+} = 2 Cr3{+} + 17 CH3COOH + 4 H2O

C21H19O2P + C7H5NO3 = C10O4H9N + C18H15OP =>
C21H19O2P + C7H5NO3 = C10O4H9N + C18H15OP

CO + H2 = C5H12 + H2O =>
5 CO + 11 H2 = C5H12 + 5 H2O

KMnO4 + SO2 + H2O = MnO2 + SO3 + KOH =>
2 KMnO4 + 3 SO2 + H2O = 2 MnO2 + 3 SO3 + 2 KOH

KMnO4 + CH3COOH + H2SO4 = CO2 + H2O + MnSO4 + K2SO4 =>
8 KMnO4 + 5 CH3COOH + 12 H2SO4 = 10 CO2 + 22 H2O + 8 MnSO4 + 4 K2SO4

Na3PO4 + CuCl2 = Na3Cl2CuPO4 =>
Na3PO4 + CuCl2 = Na3Cl2CuPO4

KCrO4 + AgSO4 = AgCrO4 + KSO4 =>
KCrO4 + AgSO4 = AgCrO4 + KSO4

H3O + FeOH = H2O + Fe =>
H3O + FeOH = 2 H2O + Fe

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Breng de vergelijking van een chemische reactie in evenwicht
 Vergelijkingen in evenwicht op de vorige dag 
Vergelijkingen in evenwicht op12/07/24
Vergelijkingen in evenwicht op11/14/24
Vergelijkingen in evenwicht op12/14/23
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