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Chemische vergelijkingen in evenwicht op12/03/24

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Breng de vergelijking van een chemische reactie in evenwicht
Se + SeO2 + HCl = Se2Cl2 + H2O =>
3 Se + SeO2 + 4 HCl = 2 Se2Cl2 + 2 H2O

HC2H3O2(aq) + LiHSO3(aq) = H2O(l) + CO2(g) + LiCH3SO2(s) =>
HC2H3O2(aq) + LiHSO3(aq) = H2O(l) + CO2(g) + LiCH3SO2(s)

MnO4{-} + Cl2{-} + H2O = MnO2 + ClO4{-} + OH{-} =>
5 MnO4{-} + Cl2{-} + 2 H2O = 5 MnO2 + 2 ClO4{-} + 4 OH{-}

H2SO4 + Al = Al2(SO4)3 + H2S + H2O =>
15 H2SO4 + 8 Al = 4 Al2(SO4)3 + 3 H2S + 12 H2O

PbO + CuO + TeO2 = PbCuTe2O6 =>
PbO + CuO + 2 TeO2 = PbCuTe2O6

KCO + NiBr = KBr + NiCO =>
KCO + NiBr = KBr + NiCO

KNO3 + CuSO4 = Cu(NO3)2 + K2SO4 =>
2 KNO3 + CuSO4 = Cu(NO3)2 + K2SO4

CaI2(aq) + K2CO3(aq) = KI(aq) + CaCO3(s) =>
CaI2(aq) + K2CO3(aq) = 2 KI(aq) + CaCO3(s)

KrO2 + H2O = KrOH + O2 =>
4 KrO2 + 2 H2O = 4 KrOH + 3 O2

KMnO4 + NaCl + H2SO4 = Cl2 + K2SO4 + MnSO4 + H2O + Na2SO4 =>
2 KMnO4 + 10 NaCl + 8 H2SO4 = 5 Cl2 + K2SO4 + 2 MnSO4 + 8 H2O + 5 Na2SO4

MnO4{-} + Cl2{-} + H2O = MnO2 + ClO4{-} + OH{-} =>
5 MnO4{-} + Cl2{-} + 2 H2O = 5 MnO2 + 2 ClO4{-} + 4 OH{-}

K2Cr2O7 + CH3COOH + PhCHO = (CH3COO)3Cr + CH3COOK + PhCOOH + H2O =>
K2Cr2O7 + 8 CH3COOH + 3 PhCHO = 2(CH3COO)3Cr + 2 CH3COOK + 3 PhCOOH + 4 H2O

MnSO4 + NaClO = Na2MnO4 + Cl2 + Na2SO4 =>
MnSO4 + 4 NaClO = Na2MnO4 + 2 Cl2 + Na2SO4

ZnS + HCl = ZnCl2 + H2S = =>
ZnS + 2 HCl = ZnCl2 + H2S

Fe + CuSO4 = FeSO4 + Cu =>
Fe + CuSO4 = FeSO4 + Cu

CoCl2H12O6 + NH4Cl + NH4OH + H2O2 = CoN6H18Cl3 + H2O =>
2 CoCl2H12O6 + 2 NH4Cl + 10 NH4OH + H2O2 = 2 CoN6H18Cl3 + 24 H2O

NH3 + Cu = Cu(NH3) =>
NH3 + Cu = Cu(NH3)

FeO + SO2 = FeS + O2 =>
2 FeO + 2 SO2 = 2 FeS + 3 O2

Bi + Cu3(PO4)2 = BiO2 + Cu3(PO)2 =>
3 Bi + Cu3(PO4)2 = 3 BiO2 + Cu3(PO)2

CaCO3 + HBr = CO2 + CaBr2 + H2O =>
CaCO3 + 2 HBr = CO2 + CaBr2 + H2O

CH2(OH){-}C(CH3)(OH){-}CH2{-}CH3 + NaOH = CH2(ONa){-}C(CH3)(ONa){-}CH2{-}CH3 + H2O =>
CH2(OH){-}C(CH3)(OH){-}CH2{-}CH3 + NaOH = CH2(ONa){-}C(CH3)(ONa){-}CH2{-}CH3 + H2O

Ag(s)O(g)H(g) + H(g)F(s) = AgF + H2O =>
Ag(s)O(g)H(g) + H(g)F(s) = AgF + H2O

HgNO3 + HCl = HgCl2 + H2O + NO2 =>
HgNO3 + 2 HCl = HgCl2 + H2O + NO2

FeSO4*7H2O + C2H2O4*2H2O = FeC2O4*2H2O + H2SO4 + H2O =>
FeSO4*7H2O + C2H2O4*2H2O = FeC2O4*2H2O + H2SO4 + 7 H2O

K + (C1)2 = KC1 =>
2 K + (C1)2 = 2 KC1

Ca(OH)2 + HNO3 = Ca(NO3)2 + H2O =>
Ca(OH)2 + 2 HNO3 = Ca(NO3)2 + 2 H2O

P + H2SO4 = H3PO4 + H2O + SO2 =>
2 P + 5 H2SO4 = 2 H3PO4 + 2 H2O + 5 SO2

Na2SO4(H2O)10 = Na2SO4(aq) + H2O =>
Na2SO4(H2O)10 = Na2SO4(aq) + 10 H2O

Ca + H2SO4(k) = CaSO4 + H2S + H2O =>
4 Ca + 5 H2SO4(k) = 4 CaSO4 + H2S + 4 H2O

HBrO + H2S = Br{-} + S8 + H{+} + H2O =>
8 HBrO + 8 H2S = 8 Br{-} + S8 + 8 H{+} + 8 H2O

C57H102O6 + CH3OH = C19H36O2 + C3H8O3 =>
2 C57H102O6 + 9 CH3OH = 6 C19H36O2 + 3 C3H8O3

Bi2O3 + Na2SnO2 = Bi + Na2SnO3 =>
Bi2O3 + 3 Na2SnO2 = 2 Bi + 3 Na2SnO3

Cr2O7{2-} + C13H10 + H{+} = Cr{3+} + C13H8O + H2O =>
2 Cr2O7{2-} + 3 C13H10 + 16 H{+} = 4 Cr{3+} + 3 C13H8O + 11 H2O

H4N2 + O2 = NO2 + H2O =>
H4N2 + 3 O2 = 2 NO2 + 2 H2O

KBr2 + KBrO3 + H2SO4 = Br2 + H2O + K2SO4 =>
10 KBr2 + 2 KBrO3 + 6 H2SO4 = 11 Br2 + 6 H2O + 6 K2SO4

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

NaOH + H2C2O4(H2O)2 = Na2C2O4 + H2O =>
2 NaOH + H2C2O4(H2O)2 = Na2C2O4 + 4 H2O

Mo2O3 + H2 = Mo + H2O =>
Mo2O3 + 3 H2 = 2 Mo + 3 H2O

HClO3 + Ba(OH)2 = Ba(ClO3)2 + H2O =>
2 HClO3 + Ba(OH)2 = Ba(ClO3)2 + 2 H2O

Cu(ii) + HNO3 = Cu(NO3)2 + NO + H2O =>
3 Cu(ii) + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O

Zn + H2CO3 = ZnCO2 + H2O =>
Zn + H2CO3 = ZnCO2 + H2O

PCl2 = P4 + Cl2 =>
4 PCl2 = P4 + 4 Cl2

HBr(aq) + Zn(OH)2(s) = ZnBr2(aq) + H2O(l) =>
2 HBr(aq) + Zn(OH)2(s) = ZnBr2(aq) + 2 H2O(l)

NH4HCO3 + Ba(OH)2 = BaCO3 + NH3 + H2O =>
NH4HCO3 + Ba(OH)2 = BaCO3 + NH3 + 2 H2O

Pb(CH3COO)2 + MgI2 = PbI2 + Mg(CH3COO)2 =>
Pb(CH3COO)2 + MgI2 = PbI2 + Mg(CH3COO)2

Zn3(C6H5O7)2*2H2O + O2 = ZnO + CO2 + H2O =>
Zn3(C6H5O7)2*2H2O + 9 O2 = 3 ZnO + 12 CO2 + 7 H2O

K2SO4(aq) + Ba(NO3)2(aq) = BaSO4(ppt) + KNO3(aq) =>
K2SO4(aq) + Ba(NO3)2(aq) = BaSO4(ppt) + 2 KNO3(aq)

NH4Cl(ac) + KNO3(ac) = N2O + KCl + H2O =>
NH4Cl(ac) + KNO3(ac) = N2O + KCl + 2 H2O

H2CO3 = H2O + CO2 =>
H2CO3 = H2O + CO2

KBr + Kl = KBrKl =>
KBr + Kl = KBrKl

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Breng de vergelijking van een chemische reactie in evenwicht
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