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Chemische vergelijkingen in evenwicht op08/03/24

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Breng de vergelijking van een chemische reactie in evenwicht
(NH4)2Co3 = (NH4) + Co2 =>
2(NH4)2Co3 = 4(NH4) + 3 Co2

KOH + Fe2(SO3)3 = Fe(OH)3 + K2SO3 =>
6 KOH + Fe2(SO3)3 = 2 Fe(OH)3 + 3 K2SO3

KI + FeCl3 = FeCl2 + I2 + KCl =>
2 KI + 2 FeCl3 = 2 FeCl2 + I2 + 2 KCl

C2H4O2 + Ca(OH)2 = C4H6CaO4 + H2O =>
2 C2H4O2 + Ca(OH)2 = C4H6CaO4 + 2 H2O

KI + FeCl3 = FeCl2 + I2 + KCl =>
2 KI + 2 FeCl3 = 2 FeCl2 + I2 + 2 KCl

N2 + O2 = NO =>
N2 + O2 = 2 NO

AlI3 + CuSO4 = Al2(SO4)3 + CuI2 =>
2 AlI3 + 3 CuSO4 = Al2(SO4)3 + 3 CuI2

KI + FeCl3 = FeCl2 + I2 + KCl =>
2 KI + 2 FeCl3 = 2 FeCl2 + I2 + 2 KCl

MgO + Ba(NO3)2 = BaO + Mg(NO3)2 =>
MgO + Ba(NO3)2 = BaO + Mg(NO3)2

LiBrO3 = LiBr + O2 =>
2 LiBrO3 = 2 LiBr + 3 O2

C2H5OH + O2 = H2O + C2H3 =>
4 C2H5OH + O2 = 6 H2O + 4 C2H3

KI + FeCl3 = FeCl2 + I2 + KCl =>
2 KI + 2 FeCl3 = 2 FeCl2 + I2 + 2 KCl

Fe + H{+} + ClO4{-} = Fe3{+} + Cl2 + H2O =>
42 Fe + 16 H{+} + 2 ClO4{-} = 14 Fe3{+} + Cl2 + 8 H2O

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

CH3COOH + Na2CO3 = CH3COONa + H2O + CO2 =>
2 CH3COOH + Na2CO3 = 2 CH3COONa + H2O + CO2

C2H5NH2 + HCl = C2H5NH3Cl =>
C2H5NH2 + HCl = C2H5NH3Cl

C2H5OH + H2O = CO + H2 =>
C2H5OH + H2O = 2 CO + 4 H2

Ra(NO3)2 + NaOH = Ra(OH)2 + NaNO3 =>
Ra(NO3)2 + 2 NaOH = Ra(OH)2 + 2 NaNO3

Cu(H2O)4(OH)2 = CuO + H2O =>
Cu(H2O)4(OH)2 = CuO + 5 H2O

FeOHCO3 = Fe2O3 + CO2 + H2O =>
2 FeOHCO3 = Fe2O3 + 2 CO2 + H2O

C20H19O10Cl + H2O = C6H12O6*H2O + HCl + C14H6O4 =>
C20H19O10Cl + H2O = C6H12O6*H2O + HCl + C14H6O4

C2H5OH + HI = C2H5I + H2O =>
C2H5OH + HI = C2H5I + H2O

NaOH + Co(NO3)2 = Co(OH)2 + NaNO3 =>
2 NaOH + Co(NO3)2 = Co(OH)2 + 2 NaNO3

MgO + LiF = MgF2 + Li2O =>
MgO + 2 LiF = MgF2 + Li2O

Al + CuSO4 = Al2(SO4)3 + Cu =>
2 Al + 3 CuSO4 = Al2(SO4)3 + 3 Cu

NO + O2 = NO2 =>
2 NO + O2 = 2 NO2

KI + FeCl3 = FeCl2 + I2 + KCl =>
2 KI + 2 FeCl3 = 2 FeCl2 + I2 + 2 KCl

C2H5OH + KMnO4 + KOH = CH3COOH + H2O + K2MnO4 =>
C2H5OH + 4 KMnO4 + 4 KOH = CH3COOH + 3 H2O + 4 K2MnO4

C6H8O7 + H3PO4 = HPO4 + C6H8 + H3O =>
2 C6H8O7 + 21 H3PO4 = 21 HPO4 + 2 C6H8 + 14 H3O

Br2 + H2O + KI = BrH2OKI =>
Br2 + 2 H2O + 2 KI = 2 BrH2OKI

C6H8O7 + H2O = CO2 + H =>
C6H8O7 + 5 H2O = 6 CO2 + 18 H

Ce(OH)4 + KI + H2SO4 = Ce2(SO4)3 + I2 + K2SO4 + H2O =>
2 Ce(OH)4 + 2 KI + 4 H2SO4 = Ce2(SO4)3 + I2 + K2SO4 + 8 H2O

MnO2 + HCl = MnCl2 + Cl2 + H2O =>
MnO2 + 4 HCl = MnCl2 + Cl2 + 2 H2O

C2H6 + F2 = CF3CHF2 + HF =>
C2H6 + 5 F2 = CF3CHF2 + 5 HF

C3H7OH + KMnO4 + H2O = CH2(OH)CH(OH)CH3 + MnO2 + KOH =>
3 C3H7OH + 2 KMnO4 + H2O = 3 CH2(OH)CH(OH)CH3 + 2 MnO2 + 2 KOH

H{+} + Cr2O7 + C2H5OH = Cr{3+} + CO2 + H2O =>
18 H{+} + 3 Cr2O7 + 2 C2H5OH = 6 Cr{3+} + 4 CO2 + 15 H2O

C2H6O(aq) + O2(g) = CO2(g) + H2O(g) =>
C2H6O(aq) + 3 O2(g) = 2 CO2(g) + 3 H2O(g)

CrCl4 + K2CO3 = K2Cl4 + CrCO3 =>
CrCl4 + K2CO3 = K2Cl4 + CrCO3

Fr + Cl2 = FrCl =>
2 Fr + Cl2 = 2 FrCl

PbCrO4 + HCl + KI = PbCl + KCl + CrCl + I2 + H2O =>
PbCrO4 + 8 HCl + 6 KI = PbCl + 6 KCl + CrCl + 3 I2 + 4 H2O

Br2O7 + KOH = Br(OH)7 + K2O =>
Br2O7 + 14 KOH = 2 Br(OH)7 + 7 K2O

Ca(OH)2 + SO4 = CaSO4 + H2O2 =>
Ca(OH)2 + SO4 = CaSO4 + H2O2

Pb(NO3)2 + (NH4)2S = PbS + NH4NO3 =>
Pb(NO3)2 + (NH4)2S = PbS + 2 NH4NO3

C7H6O3 + K2CO3 = KC7H6O3 + CO2 + H2O =>
29 C7H6O3 + 14 K2CO3 = 28 KC7H6O3 + 21 CO2 + 3 H2O

Cu(NO3)2*3H2O + NaHCO3 = CuHCO3*3H2O + Na(NO3)2 =>
Cu(NO3)2*3H2O + NaHCO3 = CuHCO3*3H2O + Na(NO3)2

C6H6O + O2(g) = H2O(g) + CO2(g) =>
C6H6O + 7 O2(g) = 3 H2O(g) + 6 CO2(g)

C6H6 + HCl = C6H5Cl + H4Cl =>
3 C6H6 + 5 HCl = 3 C6H5Cl + 2 H4Cl

Al + (HCl)3 = AlCl3 + H =>
Al + (HCl)3 = AlCl3 + 3 H

C2H6O2 = C + H + O =>
C2H6O2 = 2 C + 6 H + 2 O

H3VO4 + ClSO4 + H2SO4 = V2O2(SO4)2 + Cl(SO4)3 + H2O =>
4 H3VO4 + ClSO4 + 6 H2SO4 = 2 V2O2(SO4)2 + Cl(SO4)3 + 12 H2O

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Breng de vergelijking van een chemische reactie in evenwicht
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