Equations balanced on the previous day | Equations balanced on the next day |
3 CoMnSO4 + 4 FeCl3 + 6 H2O = 3 CoSO4 + 3 MnO2 + 12 HCl + 4 Fe
Ba + ZnPO4 = BaPO4 + Zn =>
Ba + ZnPO4 = BaPO4 + Zn
Pb(HSO4)2 + H2O = Pb + H2SO4 + O2 =>
2 Pb(HSO4)2 + 2 H2O = 2 Pb + 4 H2SO4 + O2
KOH(aq) + H3PO4(aq) = K3PO4(aq) + water =>
3 KOH(aq) + H3PO4(aq) = K3PO4(aq) + 3 H2O
Ca3P2(s) + H2O(l) = Ca(OH)2(aq) + PH3(g) =>
Ca3P2(s) + 6 H2O(l) = 3 Ca(OH)2(aq) + 2 PH3(g)
CuSO4 + Pb(NO3)2 = Cu(NO3)2 + Pb2(SO4)2 =>
2 CuSO4 + 2 Pb(NO3)2 = 2 Cu(NO3)2 + Pb2(SO4)2
HNO3 + H3PO4 + (NH4)2MoO4 = NH4NO3 + H2O + (NH4)3PO4(MoO3)12 =>
21 HNO3 + H3PO4 + 12(NH4)2MoO4 = 21 NH4NO3 + 12 H2O + (NH4)3PO4(MoO3)12
NO2 + H2O = HNO3 + N03 =>
15 NO2 + 6 H2O = 12 HNO3 + N03
NaCl + Mg(NO3)2 = MgCl + Na(NO3)2 =>
NaCl + Mg(NO3)2 = MgCl + Na(NO3)2
H2SO4NaNO2 = NaSO4H2NO2 =>
H2SO4NaNO2 = NaSO4H2NO2
PbCO3(s) = PbO(s) + CO2(g) =>
PbCO3(s) = PbO(s) + CO2(g)
NaOH + CH3OOH = H2O + Na + CH3COO =>
NaOH + 2 CH3OOH = 3 H2O + Na + CH3COO
Pt(NO3)2 + Cu = Cu(NO3)2 + Pt =>
Pt(NO3)2 + Cu = Cu(NO3)2 + Pt
C5H10 + Cl2 = HCl + C5 =>
C5H10 + 5 Cl2 = 10 HCl + C5
ZnO + K2CO3 = K2ZnO2 + CO2 =>
ZnO + K2CO3 = K2ZnO2 + CO2
(NH2)2CO + Fe(NO3)3 + Cr(NO3)3 = CO2 + Cr13Fe07O + N2 + H2O =>
179(NH2)2CO + 21 Fe(NO3)3 + 39 Cr(NO3)3 = 179 CO2 + 3 Cr13Fe07O + 269 N2 + 358 H2O
Al + Cu{+2} = Al{+3} + Cu =>
2 Al + 3 Cu{+2} = 2 Al{+3} + 3 Cu
Na2(CO3) + H(NO3) = CO2 + H(OH) + Na(NO3) =>
Na2(CO3) + 2 H(NO3) = CO2 + H(OH) + 2 Na(NO3)
Na2SO3 + H2 = S + NaOH + H2O =>
Na2SO3 + 2 H2 = S + 2 NaOH + H2O
FeCl3 + NaHCO3 = Fe2(CO3)3 + NaCl + H2O + CO2 =>
2 FeCl3 + 6 NaHCO3 = Fe2(CO3)3 + 6 NaCl + 3 H2O + 3 CO2
C5H12S(l) + O2(g) = SO2 + C5H12 =>
C5H12S(l) + O2(g) = SO2 + C5H12
HNO3 + K2CrO4 + Fe(NO3)2 = KNO3 + Cr(NO3)3 + Fe(NO3)3 + H2O =>
8 HNO3 + K2CrO4 + 3 Fe(NO3)2 = 2 KNO3 + Cr(NO3)3 + 3 Fe(NO3)3 + 4 H2O
AlCl3 + Hg(NO3)2 = HgCl2 + Al(NO3)3 =>
2 AlCl3 + 3 Hg(NO3)2 = 3 HgCl2 + 2 Al(NO3)3
C5H7O2N + O2 = CO2 + NH3 + H2O =>
C5H7O2N + 5 O2 = 5 CO2 + NH3 + 2 H2O
Li2CO3 + MnO2 = Li2MnO3 + CO2 =>
Li2CO3 + MnO2 = Li2MnO3 + CO2
NaI + K(NO3) = Na(NO3) + KI =>
NaI + K(NO3) = Na(NO3) + KI
Ba + Ni3(PO4)2 = BaNi2 + (PO4)2 =>
3 Ba + 2 Ni3(PO4)2 = 3 BaNi2 + 2(PO4)2
C8H18(l) + O2(g) = CO(g) + H2O(l) =>
2 C8H18(l) + 17 O2(g) = 16 CO(g) + 18 H2O(l)
I2 + Na2S2O3 = NaI + Na2S4O6 =>
I2 + 2 Na2S2O3 = 2 NaI + Na2S4O6
Cu(Cr2O7) + H2S = CuS + H2(Cr2O7) =>
Cu(Cr2O7) + H2S = CuS + H2(Cr2O7)
CuCl2 + Al = Cu2 + AlCl3 =>
6 CuCl2 + 4 Al = 3 Cu2 + 4 AlCl3
KOH + Na = K(NaOH) =>
KOH + Na = K(NaOH)
C3H7OH + Br2 = C3H6O + HBr =>
C3H7OH + Br2 = C3H6O + 2 HBr
KHCO3 + ClC5H10NO4 = KCl + CO2 + H2O + C5H8NO4K =>
2 KHCO3 + ClC5H10NO4 = KCl + 2 CO2 + 2 H2O + C5H8NO4K
HNO3 + Mn(OH)2 = Mn(NO3)2 + H2O =>
2 HNO3 + Mn(OH)2 = Mn(NO3)2 + 2 H2O
KOH + NiCl2 = Cl2KOH + Ni =>
KOH + NiCl2 = Cl2KOH + Ni
KClO + Cu + H2SO4 = CuSO4 + KCl + H2O =>
KClO + Cu + H2SO4 = CuSO4 + KCl + H2O
Co(H2O)6Cl2 + C5H8O2 + Na = [NaCo(C5H8O2)3] + H2O + NaCl =>
Co(H2O)6Cl2 + 3 C5H8O2 + 3 Na = [NaCo(C5H8O2)3] + 6 H2O + 2 NaCl
SrCl2 + Na2CO3(aq) = SrCO3(s) + NaCl(aq) =>
SrCl2 + Na2CO3(aq) = SrCO3(s) + 2 NaCl(aq)
KCO3 + HNO3 = HCO3 + KNO3 =>
KCO3 + HNO3 = HCO3 + KNO3
Na2HPO4 + Zn(NO3)2 = NaNO3 + ZnHPO4 =>
Na2HPO4 + Zn(NO3)2 = 2 NaNO3 + ZnHPO4
Ca(H2PO4)2 + NaOH = Ca(OH)2 + NaH2PO4 =>
Ca(H2PO4)2 + 2 NaOH = Ca(OH)2 + 2 NaH2PO4
KClO + Cu + H2SO4 = CuSO4 + KCl + H2O =>
KClO + Cu + H2SO4 = CuSO4 + KCl + H2O
NiSO4 + H2S = H2SO4 + NiS =>
NiSO4 + H2S = H2SO4 + NiS
Zr(OH)4 + HCl = ZrOCl2 + H2O =>
Zr(OH)4 + 2 HCl = ZrOCl2 + 3 H2O
Ni2C2O4 + O2 = NiO + CO2 =>
Ni2C2O4 + O2 = 2 NiO + 2 CO2
CH2O2 + CH3CH2CH2CH2OH = CH3CH2CH2COOCH3 + H2O =>
CH2O2 + CH3CH2CH2CH2OH = CH3CH2CH2COOCH3 + H2O
NaHCO3 = Na + H2 + C + O2 =>
2 NaHCO3 = 2 Na + H2 + 2 C + 3 O2
Hg + O2 = HgO =>
2 Hg + O2 = 2 HgO
Ba(OH)2 + Br2 = Ba(BrO)2 + BaBr2 + H2O =>
2 Ba(OH)2 + 2 Br2 = Ba(BrO)2 + BaBr2 + 2 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 05/27/24
Equations balanced on 06/26/23
Geef ons feedback over uw ervaring met de chemische formule balancer.