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Chemische vergelijkingen in evenwicht op05/30/24

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Breng de vergelijking van een chemische reactie in evenwicht
AlBr3(aq)Fe(NO3)3(aq) = Al(NO3)3(aq)FeBr3(s) =>
AlBr3(aq)Fe(NO3)3(aq) = Al(NO3)3(aq)FeBr3(s)

Sn + AgBr = SnBr2 + Ag =>
Sn + 2 AgBr = SnBr2 + 2 Ag

PH4I + KOH = PH3 + KI + H2O =>
PH4I + KOH = PH3 + KI + H2O

KMnO4 + FeSO4*7H2O + H2SO4 = Fe2(SO4)3 + K2SO4 + MnSO4 + H2O =>
2 KMnO4 + 10 FeSO4*7H2O + 8 H2SO4 = 5 Fe2(SO4)3 + K2SO4 + 2 MnSO4 + 78 H2O

Ca + ZnO = CaO + Zn =>
Ca + ZnO = CaO + Zn

*CaCl2(aq) + Na2CO3(aq) = CaCO3(s) + NaCl(aq) =>
*CaCl2(aq) + Na2CO3(aq) = CaCO3(s) + 2 NaCl(aq)

OCl = Cl + O =>
OCl = Cl + O

CaF2 + Li2SO4 = CaSO4 + LiF =>
CaF2 + Li2SO4 = CaSO4 + 2 LiF

MnSO4 + KBiO3 + H2SO4 = KMnO4 + Bi2(SO4)3 + K2SO4 + H2O =>
4 MnSO4 + 10 KBiO3 + 14 H2SO4 = 4 KMnO4 + 5 Bi2(SO4)3 + 3 K2SO4 + 14 H2O

FeS2 + O2 = Fe2O3 + SO2 =>
4 FeS2 + 11 O2 = 2 Fe2O3 + 8 SO2

Ba(OH)2(aq)HBr(aq) = BaBrH(OH)2 =>
Ba(OH)2(aq)HBr(aq) = BaBrH(OH)2

Fe(OH)2 + HI = FeI2 + H2O =>
Fe(OH)2 + 2 HI = FeI2 + 2 H2O

Cu(OH)2 + HBr = CuBr2 + H2O =>
Cu(OH)2 + 2 HBr = CuBr2 + 2 H2O

Fe(OH)2 + HI = FeI2 + H2O =>
Fe(OH)2 + 2 HI = FeI2 + 2 H2O

Cl2 + NaOH = NaClO3 + NaCl + H2O =>
3 Cl2 + 6 NaOH = NaClO3 + 5 NaCl + 3 H2O

HC2H3O2 + K2SO4 = KC2H3O2 + H2SO4 =>
2 HC2H3O2 + K2SO4 = 2 KC2H3O2 + H2SO4

PH3 + HMnO4 = MnO2 + H2PO4 + H2O =>
PH3 + 3 HMnO4 = 3 MnO2 + H2PO4 + 2 H2O

CO + Al = AlO + C =>
CO + Al = AlO + C

Fe(OH)2 + HI = FeI2 + H2O =>
Fe(OH)2 + 2 HI = FeI2 + 2 H2O

Cu(OH)2 + HBr = CuBr2 + H2O =>
Cu(OH)2 + 2 HBr = CuBr2 + 2 H2O

Fe(OH)2 + HI = FeI2 + H2O =>
Fe(OH)2 + 2 HI = FeI2 + 2 H2O

C19H28O2 + O2 = CO2 + H2O =>
C19H28O2 + 25 O2 = 19 CO2 + 14 H2O

Fe(OH)2 + HI = FeI2 + H2O =>
Fe(OH)2 + 2 HI = FeI2 + 2 H2O

Cu(OH)2 + HBr = CuBr2 + H2O =>
Cu(OH)2 + 2 HBr = CuBr2 + 2 H2O

CrCl2 + NaOH = Cr(OH) + NaCl2 =>
CrCl2 + NaOH = Cr(OH) + NaCl2

Cu(OH)2 + HBr = CuBr2 + H2O =>
Cu(OH)2 + 2 HBr = CuBr2 + 2 H2O

Cu + HNO3(dilute) = Cu(NO3)2 + H2O + NO2 =>
Cu + 4 HNO3(dilute) = Cu(NO3)2 + 2 H2O + 2 NO2

Fe(OH)2 + HI = FeI2 + H2O =>
Fe(OH)2 + 2 HI = FeI2 + 2 H2O

C8H8 + Br2 = C8H7Br + HBr =>
C8H8 + Br2 = C8H7Br + HBr

Cu(OH)2 + HBr = CuBr2 + H2O =>
Cu(OH)2 + 2 HBr = CuBr2 + 2 H2O

HBr + Bi(OH)3 = BiBr3 + H2O =>
3 HBr + Bi(OH)3 = BiBr3 + 3 H2O

CuSO4 + Al + HCl = Cu + AlCl3 + H2SO4 =>
3 CuSO4 + 2 Al + 6 HCl = 3 Cu + 2 AlCl3 + 3 H2SO4

Cu(OH)2 + HBr = CuBr2 + H2O =>
Cu(OH)2 + 2 HBr = CuBr2 + 2 H2O

CuSO4 + Al + HCl = Cu + AlCl3 + H2SO4 =>
3 CuSO4 + 2 Al + 6 HCl = 3 Cu + 2 AlCl3 + 3 H2SO4

Al + HCl + CuSO4 = Al2(SO4)3 + CuCl2 + H2 =>
2 Al + 6 HCl + 3 CuSO4 = Al2(SO4)3 + 3 CuCl2 + 3 H2

HBr + Bi(OH)3 = BiBr3 + H2O =>
3 HBr + Bi(OH)3 = BiBr3 + 3 H2O

Br2 + CoI3 = I2 + CoBr3 =>
3 Br2 + 2 CoI3 = 3 I2 + 2 CoBr3

Al2(CO3)3 + CH3COOH = CH3COOAl + H2O + CO2 =>
2 Al2(CO3)3 + 5 CH3COOH = 4 CH3COOAl + 4 H2O + 8 CO2

Al + HCl + CuSO4 = Al2(SO4)3 + CuCl2 + H2 =>
2 Al + 6 HCl + 3 CuSO4 = Al2(SO4)3 + 3 CuCl2 + 3 H2

HBr + Bi(OH)3 = BiBr3 + H2O =>
3 HBr + Bi(OH)3 = BiBr3 + 3 H2O

CuSO4 + Al + HCl = Cu + AlCl3 + H2SO4 =>
3 CuSO4 + 2 Al + 6 HCl = 3 Cu + 2 AlCl3 + 3 H2SO4

Cu(OH)2 + HBr = CuBr2 + H2O =>
Cu(OH)2 + 2 HBr = CuBr2 + 2 H2O

HBr + Bi(OH)3 = H2O + Bi(OH)Br2 =>
2 HBr + Bi(OH)3 = 2 H2O + Bi(OH)Br2

C4H8CO3 + O2 = CO2 + H2O =>
2 C4H8CO3 + 11 O2 = 10 CO2 + 8 H2O

Cu(OH)2 + HBr = CuBr2 + H2O =>
Cu(OH)2 + 2 HBr = CuBr2 + 2 H2O

Al + HCl + CuSO4 = Al2(SO4)3 + CuCl2 + H2 =>
2 Al + 6 HCl + 3 CuSO4 = Al2(SO4)3 + 3 CuCl2 + 3 H2

CU(OH)2 + HBr = CUBr2 + H2O =>
CU(OH)2 + 2 HBr = CUBr2 + 2 H2O

Bi(NO3)3*5H2O + KI = BiOI + KNO3 + HNO3 + H2O =>
Bi(NO3)3*5H2O + KI = BiOI + KNO3 + 2 HNO3 + 4 H2O

(NH4)2CO3(s) = CO2(g) + NH3(g) + H2O(g) =>
(NH4)2CO3(s) = CO2(g) + 2 NH3(g) + H2O(g)

HBr + Bi(OH)3 = BiBr3 + H2O =>
3 HBr + Bi(OH)3 = BiBr3 + 3 H2O

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Breng de vergelijking van een chemische reactie in evenwicht
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