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Chemische vergelijkingen in evenwicht op05/26/24

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Breng de vergelijking van een chemische reactie in evenwicht
XYNa2SO4(aq) = Na2Y(aq)XSO4(aq) =>
XYNa2SO4(aq) = Na2Y(aq)XSO4(aq)

P + KOH + H2O = PH3 + KH2PO4 =>
8 P + 3 KOH + 9 H2O = 5 PH3 + 3 KH2PO4

HCOOH + Fe(OH)2 = (HCOO)2Fe + H2O =>
2 HCOOH + Fe(OH)2 = (HCOO)2Fe + 2 H2O

KAl(OH)4 + HCl = KCl + Al(OH)3 + H2O =>
KAl(OH)4 + HCl = KCl + Al(OH)3 + H2O

HBr(aq)C5H6N(aq) = C5H5(l)NH2Br(l) =>
HBr(aq)C5H6N(aq) = C5H5(l)NH2Br(l)

K2Cr2O7 + Cu = K2Cu2O7 + Cr =>
K2Cr2O7 + 2 Cu = K2Cu2O7 + 2 Cr

COCl2 + NH4OH = COOH + Cl2NH4 =>
COCl2 + NH4OH = COOH + Cl2NH4

C5H12 + H2O = H + CO =>
C5H12 + 5 H2O = 22 H + 5 CO

Mg + Sn(NO2)4 = Sn + Mg(NO2)2 =>
2 Mg + Sn(NO2)4 = Sn + 2 Mg(NO2)2

CuSO4 + HCl + NaOH = CuCl2 + Na2SO4 + H2O =>
CuSO4 + 2 HCl + 2 NaOH = CuCl2 + Na2SO4 + 2 H2O

HCOOH + Fe(OH)2 = (HCOO)2Fe + H2O =>
2 HCOOH + Fe(OH)2 = (HCOO)2Fe + 2 H2O

K2S2O3 + HBr = KBr + SO3 + H2S =>
K2S2O3 + 2 HBr = 2 KBr + SO3 + H2S

K2CO3 + NaNO3 = K2NO3 + NaCO3 =>
K2CO3 + NaNO3 = K2NO3 + NaCO3

CO + K2Cr2O7 + H2SO4 = CO2 + KSO4 + CrSO4 + H2O =>
3 CO + K2Cr2O7 + 4 H2SO4 = 3 CO2 + 2 KSO4 + 2 CrSO4 + 4 H2O

HC2H3O2(aq)NaHSO3(aq) = NaC2H3O2(aq)H2O(l)SO2(g) =>
HC2H3O2(aq)NaHSO3(aq) = NaC2H3O2(aq)H2O(l)SO2(g)

HNO3 + Cu = Cu(NO3)2 + NO2(aq) + H2O =>
4 HNO3 + Cu = Cu(NO3)2 + 2 NO2(aq) + 2 H2O

AgNO3 + Al2O3 + e = AgAl{-} + O2 + N4 =>
4 AgNO3 + 2 Al2O3 + 4e = 4 AgAl{-} + 9 O2 + N4

C3H7COOH + MgCO3 = (C3H7COO)2Mg + CO2 + H2O =>
2 C3H7COOH + MgCO3 = (C3H7COO)2Mg + CO2 + H2O

TiCl3 + Fe2(SO4)3 = FeCl3 + Ti2(SO4)3 =>
2 TiCl3 + Fe2(SO4)3 = 2 FeCl3 + Ti2(SO4)3

CH3CH(OH)CH3 + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO2 + CH3COH + H2O =>
10 CH3CH(OH)CH3 + 3 K2Cr2O7 + 12 H2SO4 = 3 Cr2(SO4)3 + 3 K2SO2 + 15 CH3COH + 22 H2O

CO2 + CaCl2 + H2O = HCl + CaCO3 =>
CO2 + CaCl2 + H2O = 2 HCl + CaCO3

MnO4{-} = MnO4{-}2 =>
MnO4{-} = MnO4{-}2

K2MnO4 + CH3OH + H2O = MnO2 + HCOOH + KOH =>
2 K2MnO4 + CH3OH + H2O = 2 MnO2 + HCOOH + 4 KOH

HCl + K2CrO4 + H2C2O4 = CO2 + CrCl2 + KCl + H2O =>
4 HCl + K2CrO4 + 2 H2C2O4 = 4 CO2 + CrCl2 + 2 KCl + 4 H2O

TiO2 + C + Cl2 = TiCl5 + CO2 =>
2 TiO2 + 2 C + 5 Cl2 = 2 TiCl5 + 2 CO2

NaBr + NH3 = NaNH2 + HBr =>
NaBr + NH3 = NaNH2 + HBr

Ag(s) + S8(g) = Ag2S =>
16 Ag(s) + S8(g) = 8 Ag2S

MgSO4(H2O)7 + NaHCO3 = Mg(HCO3)2 + Na2SO4 + H2O =>
MgSO4(H2O)7 + 2 NaHCO3 = Mg(HCO3)2 + Na2SO4 + 7 H2O

Mg + HNO3 = Mg(NO3)2 + HN4NO3 + H2O =>
10 Mg + 25 HNO3 = 10 Mg(NO3)2 + HN4NO3 + 12 H2O

C10H10O4 + NaBH4 = C10H12O4 + NaBH2 =>
C10H10O4 + NaBH4 = C10H12O4 + NaBH2

Fe2O3 + H2O = Fe(OH)3 =>
Fe2O3 + 3 H2O = 2 Fe(OH)3

Fe2O3 + H2 = Fe + H2O =>
Fe2O3 + 3 H2 = 2 Fe + 3 H2O

CuSO4 + Pb(OAc)2 = PbSO4 + Cu(OAc)2 =>
CuSO4 + Pb(OAc)2 = PbSO4 + Cu(OAc)2

(NH4)2SO4 + Mn(C2H3O2)2 = NH4(C2H3O2) + MnSO4 =>
(NH4)2SO4 + Mn(C2H3O2)2 = 2 NH4(C2H3O2) + MnSO4

KCl + KNO2 + H2SO4 = K2SO4 + N2 + Cl2 + H2O =>
6 KCl + 2 KNO2 + 4 H2SO4 = 4 K2SO4 + N2 + 3 Cl2 + 4 H2O

K3PO4 + NaNO3 = KNO3 + Na3PO4 =>
K3PO4 + 3 NaNO3 = 3 KNO3 + Na3PO4

NH3 + C2H4O3 = C2H3O3NH2 + H2 =>
NH3 + C2H4O3 = C2H3O3NH2 + H2

Pb(CH3CO2)2(aq) + (NH4)2CrO4(aq) = PbCrO4(s) + NH4CH3CO2 =>
Pb(CH3CO2)2(aq) + (NH4)2CrO4(aq) = PbCrO4(s) + 2 NH4CH3CO2

Cu(NO3)2 + Na2CrO4 = CuCrO4 + (NO3)Na =>
Cu(NO3)2 + Na2CrO4 = CuCrO4 + 2(NO3)Na

HCl + BaSiO3 = BaCl2 + H2SiO3 =>
2 HCl + BaSiO3 = BaCl2 + H2SiO3

Na2CrO4 + Pb(C2H3O2)2 = Na2(C2H3O2)2 + PbCrO4 =>
Na2CrO4 + Pb(C2H3O2)2 = Na2(C2H3O2)2 + PbCrO4

KCl + PbO2 + HNO3 = Pb(NO3)2 + Cl2 + KNO3 + H2O =>
2 KCl + PbO2 + 4 HNO3 = Pb(NO3)2 + Cl2 + 2 KNO3 + 2 H2O

RuCl4(s) + Na2S4(s) = RuS2(s) + NaCl(s) + S(s) =>
RuCl4(s) + 2 Na2S4(s) = RuS2(s) + 4 NaCl(s) + 6 S(s)

C3H7OHHCl = C3H7OClH2 =>
C3H7OHHCl = C3H7OClH2

CuSO4Cu(OH)2 + (NH4)2SO4 + NH4OH = (Cu(NH3)4)SO4 + H2O =>
CuSO4Cu(OH)2 + (NH4)2SO4 + 6 NH4OH = 2(Cu(NH3)4)SO4 + 8 H2O

V(OH)5 + FeSO4 = Fe(OH)3 + V2O4 + H2SO4 =>
2 V(OH)5 + 2 FeSO4 = 2 Fe(OH)3 + V2O4 + 2 H2SO4

(NH4)2S + Fe(No3)2 = FeS + (NH4)2(No3)2 =>
(NH4)2S + Fe(No3)2 = FeS + (NH4)2(No3)2

C3H8 + O = C3O + OH8 =>
C3H8 + 2 O = C3O + OH8

Al(s) + Mn2O3(s) = Mn(s) + Al2O3 =>
2 Al(s) + Mn2O3(s) = 2 Mn(s) + Al2O3

Ba(OH)2 + (NH4)2CrO4 = BaCrO4 + NH4OH =>
Ba(OH)2 + (NH4)2CrO4 = BaCrO4 + 2 NH4OH

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Breng de vergelijking van een chemische reactie in evenwicht
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