Equations balanced on the previous day | Equations balanced on the next day |
B4C3 + 12 H2O = 3 CH4 + 4 B(OH)3
NaCl + NaClO + H2SO4 = Cl2 + Na2SO4 + H2O =>
NaCl + NaClO + H2SO4 = Cl2 + Na2SO4 + H2O
K + H20O = KOH + H2 =>
2 K + 2 H20O = 2 KOH + 19 H2
NaI + Pb(SO4)2 = PbI + Na2 + SO4 =>
2 NaI + 2 Pb(SO4)2 = 2 PbI + Na2 + 4 SO4
CaICuP = ICuCaP =>
CaICuP = ICuCaP
Nb + CoO = Co3Nb + NbO =>
4 Nb + 3 CoO = Co3Nb + 3 NbO
MgBr2 + F2 = Mg2 + FBr =>
2 MgBr2 + 2 F2 = Mg2 + 4 FBr
NO + CO(NH2)2 = N2 + H2O + CO =>
2 NO + CO(NH2)2 = 2 N2 + 2 H2O + CO
CH3CHO + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO2 + CH3CH2COOH + H2O =>
15 CH3CHO + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO2 + 10 CH3CH2COOH + 4 H2O
CH3CHO + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO2 + CH3CH2COOH + H2O =>
15 CH3CHO + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO2 + 10 CH3CH2COOH + 4 H2O
N2 + O2 = N2O5 =>
2 N2 + 5 O2 = 2 N2O5
C27H46O + Br2 = C27H44OBr2 + H2 =>
C27H46O + Br2 = C27H44OBr2 + H2
CH3CHO + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO2 + CH3CH2COOH + H2O =>
15 CH3CHO + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO2 + 10 CH3CH2COOH + 4 H2O
C12H26 + KAl(SO4)2*12(H2O) = KAl(SO4)2*11(H2O) + C12H25O + H =>
C12H26 + KAl(SO4)2*12(H2O) = KAl(SO4)2*11(H2O) + C12H25O + 3 H
CH3CHO + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO2 + CH3CH2COOH + H2O =>
15 CH3CHO + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO2 + 10 CH3CH2COOH + 4 H2O
PotassiumFluoride + BariumBromide = BariumFluoride + PotassiumBromide =>
2 KF + BaBr2 = BaF2 + 2 KBr
K2Cr2O7 + H2SO4 + CuI = CuSO4 + K2SO4 + I2 + Cr2(SO4)3 + H2O =>
2 K2Cr2O7 + 14 H2SO4 + 6 CuI = 6 CuSO4 + 2 K2SO4 + 3 I2 + 2 Cr2(SO4)3 + 14 H2O
Al2(SO4)3 + K3Po4 = AlPo4 + K2SO4 =>
Al2(SO4)3 + 2 K3Po4 = 2 AlPo4 + 3 K2SO4
Sb2O3 + KMnO4 + H2SO4 = MnSO4 + K2SO4 + Sb2O5 + H2O =>
5 Sb2O3 + 4 KMnO4 + 6 H2SO4 = 4 MnSO4 + 2 K2SO4 + 5 Sb2O5 + 6 H2O
K2CO3 + H2O = KHCO3 + KOH =>
K2CO3 + H2O = KHCO3 + KOH
BaCl2 + NaC12H24O2 = Ba(C12H24O2)2 + NaCl =>
BaCl2 + 2 NaC12H24O2 = Ba(C12H24O2)2 + 2 NaCl
Zn + Ca = ZnCa2 =>
Zn + 2 Ca = ZnCa2
SiO2 + NaOH = Na2SiO3 + H2O =>
SiO2 + 2 NaOH = Na2SiO3 + H2O
NH4Cl(aq) + KNO3(aq) = NH4NO3(aq) + KCl(aq) =>
NH4Cl(aq) + KNO3(aq) = NH4NO3(aq) + KCl(aq)
H2O1 + PCl3 = H3PO3 + HCl =>
3 H2O1 + PCl3 = H3PO3 + 3 HCl
Cl2 + KI2 = I2 + KCl2 =>
Cl2 + KI2 = I2 + KCl2
CuSO4 + NaOH + C6H10O5 = Cu2O + Na2SO4 + C6H12O7 + H2O =>
2 CuSO4 + 4 NaOH + C6H10O5 = Cu2O + 2 Na2SO4 + C6H12O7 + H2O
C2H5OH + C2H5Br = C2H5OC2H5 + HBr =>
C2H5OH + C2H5Br = C2H5OC2H5 + HBr
SiO2 + C = CO + Si =>
SiO2 + 2 C = 2 CO + Si
CH3CHO + K2Cr2O7 + H2SO4 = CH3COOH + K2SO4 + Cr2(SO4)3 + H2O =>
3 CH3CHO + K2Cr2O7 + 4 H2SO4 = 3 CH3COOH + K2SO4 + Cr2(SO4)3 + 4 H2O
C6H12O6 + H3PO4 = C6H13O9P + H2O =>
C6H12O6 + H3PO4 = C6H13O9P + H2O
Fe + HCl = FeCl2 + H2 =>
Fe + 2 HCl = FeCl2 + H2
K2Cr2O7 + SnCl2 + H2SO4 = Sn(SO4)2 + SnCl4 + Cr2(SO4)3 + K2SO4 + H2O =>
2 K2Cr2O7 + 6 SnCl2 + 14 H2SO4 = 3 Sn(SO4)2 + 3 SnCl4 + 2 Cr2(SO4)3 + 2 K2SO4 + 14 H2O
FeSO4 + AgNO3 = Fe(NO3)2 + Ag2SO4 =>
FeSO4 + 2 AgNO3 = Fe(NO3)2 + Ag2SO4
CH3CHO + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO2 + CH3CH2COOH + H2O =>
15 CH3CHO + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO2 + 10 CH3CH2COOH + 4 H2O
KHSO4 + Ca5(H2PO4)3F = K2SO4 + CaSO4 + HF + H + P + O =>
10 KHSO4 + Ca5(H2PO4)3F = 5 K2SO4 + 5 CaSO4 + HF + 15 H + 3 P + 12 O
FeO + Na = Na2O + Fe =>
FeO + 2 Na = Na2O + Fe
Al + Fe2O3 = Al2O3 + Fe =>
2 Al + Fe2O3 = Al2O3 + 2 Fe
ClO2 + NO2 = Cl2 + NO3 =>
2 ClO2 + 4 NO2 = Cl2 + 4 NO3
H2O1 + PCl3 = H3PO3 + HCl =>
3 H2O1 + PCl3 = H3PO3 + 3 HCl
AlOH = AlO + H2 =>
2 AlOH = 2 AlO + H2
Ba + Sn(HCO3)4 = Ba(HCO3)2 + Sn =>
2 Ba + Sn(HCO3)4 = 2 Ba(HCO3)2 + Sn
H2O1 + PCl3 = H3PO3 + HCl =>
3 H2O1 + PCl3 = H3PO3 + 3 HCl
Cu(OH)2 + AlPO4 = Cu3(PO4)2 + Al(OH)3 =>
3 Cu(OH)2 + 2 AlPO4 = Cu3(PO4)2 + 2 Al(OH)3
NaI + H2SO4 = H2S + I2 + NaHSO4 + H2O =>
8 NaI + 9 H2SO4 = H2S + 4 I2 + 8 NaHSO4 + 4 H2O
Ba + Sn(HCO3)4 = Ba(HCO3)2 + Sn =>
2 Ba + Sn(HCO3)4 = 2 Ba(HCO3)2 + Sn
Cr(OH)3 + IO3{-} + OH{-} = CrO4{2-} + I{-} + H2O =>
2 Cr(OH)3 + IO3{-} + 4 OH{-} = 2 CrO4{2-} + I{-} + 5 H2O
C5H12OH + HBr = C5H12Br + H2O =>
C5H12OH + HBr = C5H12Br + H2O
Ba + Sn(HCO3)4 = Ba(HCO3)2 + Sn =>
2 Ba + Sn(HCO3)4 = 2 Ba(HCO3)2 + Sn
Ba + Sn(HCO3)4 = Ba(HCO3)2 + Sn =>
2 Ba + Sn(HCO3)4 = 2 Ba(HCO3)2 + Sn
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Equations balanced on 02/19/24
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