Equations balanced on the previous day | Equations balanced on the next day |
2 KClO3 + 3 MnSO4 + 6 K2CO3 = 3 K2MnO4 + 2 KCl + 3 K2SO4 + 6 CO2
C + H2 + Br2 = CH3Br =>
2 C + 3 H2 + Br2 = 2 CH3Br
CaCO3(s) + HBr(aq) = CaBr2(aq) + CO2(g) + H2O(l) =>
CaCO3(s) + 2 HBr(aq) = CaBr2(aq) + CO2(g) + H2O(l)
MnO = Mn2 + O3 =>
6 MnO = 3 Mn2 + 2 O3
Ag + NaOH = AgNaOH =>
Ag + NaOH = AgNaOH
K2Cr2O7 + KI + H2SO4 = I2 + Cr2(SO4)3 + KSO4 + H2O =>
K2Cr2O7 + 2 KI + 7 H2SO4 = I2 + Cr2(SO4)3 + 4 KSO4 + 7 H2O
NaOH + H2CO3 = Na2CO3 + H2O =>
2 NaOH + H2CO3 = Na2CO3 + 2 H2O
KJ + KJO3 + H2SO4 = K2SO4 + JSO4 + H2O =>
KJ + KJO3 + 3 H2SO4 = K2SO4 + 2 JSO4 + 3 H2O
Mg + NHO3 = MgNO3 + H2 =>
2 Mg + 2 NHO3 = 2 MgNO3 + H2
B5H9 + O2 = B6O3 + H2O =>
6 B5H9 + 21 O2 = 5 B6O3 + 27 H2O
FeI2 + H2SO4 = Fe2(SO4)3 + S2O + I2 + H2O =>
10 FeI2 + 21 H2SO4 = 5 Fe2(SO4)3 + 3 S2O + 10 I2 + 21 H2O
Mn(NO3)2 + KBiO3 + HNO3 = Bi(NO3)3 + KMnO4 + H2O + KNO3 =>
2 Mn(NO3)2 + 5 KBiO3 + 14 HNO3 = 5 Bi(NO3)3 + 2 KMnO4 + 7 H2O + 3 KNO3
RbCl + K2SO4 = Rb2SO4 + KCl =>
2 RbCl + K2SO4 = Rb2SO4 + 2 KCl
Na2B4O7 + H2O + HNO3 = H3BO3 + NaNO3 =>
Na2B4O7 + 5 H2O + 2 HNO3 = 4 H3BO3 + 2 NaNO3
NH4(NO3) + H2O = NH4 + HNO3 =>
9 NH4(NO3) + 3 H2O = 8 NH4 + 10 HNO3
B5H9 + O2 = B6O3 + H2O =>
6 B5H9 + 21 O2 = 5 B6O3 + 27 H2O
KICo = KCoI =>
KICo = KCoI
C3H8O + O2 = CO2 + H2O =>
2 C3H8O + 9 O2 = 6 CO2 + 8 H2O
(NH4)2SO4 + Mn(C2H3O2)2 = NH4(C2H3O2) + Mn(SO4) =>
(NH4)2SO4 + Mn(C2H3O2)2 = 2 NH4(C2H3O2) + Mn(SO4)
SrO + Cl2 = Sr + ClO =>
2 SrO + Cl2 = 2 Sr + 2 ClO
Pb(CH3COO)2 + BaCl = PbCl + Ba(CH3COO)2 =>
Pb(CH3COO)2 + BaCl = PbCl + Ba(CH3COO)2
B + Se = B2Se3 =>
2 B + 3 Se = B2Se3
NH4(NO3) + H2O = NH4 + HNO3 =>
9 NH4(NO3) + 3 H2O = 8 NH4 + 10 HNO3
CdCl2O8 + NaOH = NaClO4 + Cd(OH)2 =>
CdCl2O8 + 2 NaOH = 2 NaClO4 + Cd(OH)2
KI + H2SO4 + NaNO2 = I2 + NO + K2SO4 + Na2SO4 + H2O =>
2 KI + 2 H2SO4 + 2 NaNO2 = I2 + 2 NO + K2SO4 + Na2SO4 + 2 H2O
Mn(NO3)2 + KBiO3 + HNO3 = Bi(NO3)3 + KMnO4 + H2O + KNO3 =>
2 Mn(NO3)2 + 5 KBiO3 + 14 HNO3 = 5 Bi(NO3)3 + 2 KMnO4 + 7 H2O + 3 KNO3
Ba(NO3)2 + NaOH = Ba(OH)2 + Na(NO3) =>
Ba(NO3)2 + 2 NaOH = Ba(OH)2 + 2 Na(NO3)
Pb(CH3COO)2 + BaCl = PbCl + Ba(CH3COO)2 =>
Pb(CH3COO)2 + BaCl = PbCl + Ba(CH3COO)2
NH4(NO3) + H2O = NH4 + HNO3 =>
9 NH4(NO3) + 3 H2O = 8 NH4 + 10 HNO3
RbCl + K2SO4 = Rb2SO4 + KCl =>
2 RbCl + K2SO4 = Rb2SO4 + 2 KCl
Na2CO3(aq) + AgNO3(aq) = Ag2CO3(s) + NaNO3 =>
Na2CO3(aq) + 2 AgNO3(aq) = Ag2CO3(s) + 2 NaNO3
CdCl2O8 + NaOH = NaClO4 + Cd(OH)2 =>
CdCl2O8 + 2 NaOH = 2 NaClO4 + Cd(OH)2
Na2B4O7 + H2O + HNO3 = H3BO3 + NaNO3 =>
Na2B4O7 + 5 H2O + 2 HNO3 = 4 H3BO3 + 2 NaNO3
KI + NO3 = KNO3 + I =>
KI + NO3 = KNO3 + I
AlOH + HBr = AlBr + H2O =>
AlOH + HBr = AlBr + H2O
SrO + Cl2 = Sr + ClO =>
2 SrO + Cl2 = 2 Sr + 2 ClO
Na2B4O7 + H2O + HNO3 = H3BO3 + NaNO3 =>
Na2B4O7 + 5 H2O + 2 HNO3 = 4 H3BO3 + 2 NaNO3
RbCl + K2SO4 = Rb2SO4 + KCl =>
2 RbCl + K2SO4 = Rb2SO4 + 2 KCl
CdCl2O8 + NaOH = NaClO4 + Cd(OH)2 =>
CdCl2O8 + 2 NaOH = 2 NaClO4 + Cd(OH)2
NH4(NO3) + H2O = NH4 + HNO3 =>
9 NH4(NO3) + 3 H2O = 8 NH4 + 10 HNO3
Mn(NO3)2 + KBiO3 + HNO3 = Bi(NO3)3 + KMnO4 + H2O + KNO3 =>
2 Mn(NO3)2 + 5 KBiO3 + 14 HNO3 = 5 Bi(NO3)3 + 2 KMnO4 + 7 H2O + 3 KNO3
B5H9 + O2 = B6O3 + H2O =>
6 B5H9 + 21 O2 = 5 B6O3 + 27 H2O
B5H9 + O2 = B6O3 + H2O =>
6 B5H9 + 21 O2 = 5 B6O3 + 27 H2O
NH4(NO3) + H2O = NH4 + HNO3 =>
9 NH4(NO3) + 3 H2O = 8 NH4 + 10 HNO3
Mn(NO3)2 + KBiO3 + HNO3 = Bi(NO3)3 + KMnO4 + H2O + KNO3 =>
2 Mn(NO3)2 + 5 KBiO3 + 14 HNO3 = 5 Bi(NO3)3 + 2 KMnO4 + 7 H2O + 3 KNO3
Na2B4O7 + H2O + HNO3 = H3BO3 + NaNO3 =>
Na2B4O7 + 5 H2O + 2 HNO3 = 4 H3BO3 + 2 NaNO3
Pb(CH3COO)2 + BaCl = PbCl + Ba(CH3COO)2 =>
Pb(CH3COO)2 + BaCl = PbCl + Ba(CH3COO)2
V + Cl2 = VCl =>
2 V + Cl2 = 2 VCl
C4H10O3 + O2 = CO2 + H2O =>
C4H10O3 + 5 O2 = 4 CO2 + 5 H2O
RbCl + K2SO4 = Rb2SO4 + KCl =>
2 RbCl + K2SO4 = Rb2SO4 + 2 KCl
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/30/23
Equations balanced on 01/29/23
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