Equations balanced on the previous day | Equations balanced on the next day |
C2F2 + Mg = MgF2 + 2 C
Fe2(SO4)3 + K3[Fe(CN)6] = Fe[Fe(CN)6] + K2SO4 =>
Fe2(SO4)3 + 2 K3[Fe(CN)6] = 2 Fe[Fe(CN)6] + 3 K2SO4
C7H14 + HBr = CBr4 + H2 =>
C7H14 + 28 HBr = 7 CBr4 + 21 H2
Na2Cr2O7 + NaNO2 + H2SO4 = NaNO3 + Cr2(SO4)3 + Na2SO4 + H2O =>
Na2Cr2O7 + 3 NaNO2 + 4 H2SO4 = 3 NaNO3 + Cr2(SO4)3 + Na2SO4 + 4 H2O
CuO3 + H2SO4 = H2O + CuO2 + SO4 =>
CuO3 + H2SO4 = H2O + CuO2 + SO4
NH3 + Cu2O = [Cu(NH3)]2 + O2 =>
4 NH3 + 2 Cu2O = 2[Cu(NH3)]2 + O2
CH3CH2CH2CH2OH + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3CH2CH2CHCOOH + H2O =>
15 CH3CH2CH2CH2OH + 10 K2Cr2O7 + 40 H2SO4 = 10 Cr2(SO4)3 + 10 K2SO4 + 12 CH3CH2CH2CHCOOH + 61 H2O
Pb(CH3COO)2 + NaCl = PbCl2 + CH3COONa =>
Pb(CH3COO)2 + 2 NaCl = PbCl2 + 2 CH3COONa
Zn(NO3)2 + Ba(OH)2 = Ba[Zn(OH)4] + Ba(NO3)2 =>
Zn(NO3)2 + 2 Ba(OH)2 = Ba[Zn(OH)4] + Ba(NO3)2
C3H8 + Cl2 = C3H7Cl + HCl =>
C3H8 + Cl2 = C3H7Cl + HCl
AgCl + NaOH = Ag2O + NaCl + H2O =>
2 AgCl + 2 NaOH = Ag2O + 2 NaCl + H2O
Pb(CH3COO)4 + Ca(OH)2 = Pb(OH)4 + Ca(CH3COO)2 =>
Pb(CH3COO)4 + 2 Ca(OH)2 = Pb(OH)4 + 2 Ca(CH3COO)2
HCOHAg2O = HCOOHAg2 =>
HCOHAg2O = HCOOHAg2
ClO3 = O2 + Cl =>
2 ClO3 = 3 O2 + 2 Cl
CH4 + NO2 = N2 + CO2 + HO =>
2 CH4 + 6 NO2 = 3 N2 + 2 CO2 + 8 HO
MgCl2 + Pb(NO3)2 = Mg(NO3)2 + Pb(Cl)2 =>
MgCl2 + Pb(NO3)2 = Mg(NO3)2 + Pb(Cl)2
KNO{3+} + H{2+}CO{3+} = K{2+}CO{2+} + HNO{3{+} =>
KNO{3+} + H{2+}CO{3+} = K{2+}CO{2+} + HNO{3{+}
CoCl2 + K2HPO4 = Co3(PO4)2 + HCl + KCl =>
3 CoCl2 + 2 K2HPO4 = Co3(PO4)2 + 2 HCl + 4 KCl
KOH + H2CrO4 = KHCrO4 + H2O =>
KOH + H2CrO4 = KHCrO4 + H2O
CoF3 + Na2O = Co2O3 + NaF =>
2 CoF3 + 3 Na2O = Co2O3 + 6 NaF
Al2O3 + N2O3 = Al(NO3)3 + NO =>
Al2O3 + 9 N2O3 = 2 Al(NO3)3 + 12 NO
F2 + PbCl2 = FCl + Pb =>
F2 + PbCl2 = 2 FCl + Pb
NaHCO3 + N2 = Na + HCN + O3 =>
2 NaHCO3 + N2 = 2 Na + 2 HCN + 2 O3
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3 =>
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3 =>
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3
(NH4)2 + I = NH4I =>
(NH4)2 + 2 I = 2 NH4I
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3 =>
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3
Al(OH)3 + H3ClO = AlCl3 + H2O =>
Al(OH)3 + 3 H3ClO = AlCl3 + 6 H2O
Cl2 + KI = K + ClI =>
Cl2 + 2 KI = 2 K + 2 ClI
KH2PO4 + BaCl2 = BaPO4 + KH2Cl2 =>
KH2PO4 + BaCl2 = BaPO4 + KH2Cl2
Ba(OH)2 + HIO3 = BaHIO4 + H2O =>
Ba(OH)2 + HIO3 = BaHIO4 + H2O
C6H6 + CH4 = C6H12 =>
2 C6H6 + 6 CH4 = 3 C6H12
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3 =>
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3
Pb + FeC2H3O2 = PbFe + C2H3O2 =>
Pb + FeC2H3O2 = PbFe + C2H3O2
TiO2 + CO = Ti7O13 + CO2 =>
7 TiO2 + CO = Ti7O13 + CO2
I2 + OH = IO3 + H2O =>
I2 + 12 OH = 2 IO3 + 6 H2O
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3 =>
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3
Ag2S + NaCl = AgCl + Na2S =>
Ag2S + 2 NaCl = 2 AgCl + Na2S
H2SO4 + KI = HKSO4 + I2 + H2O + H2S =>
9 H2SO4 + 8 KI = 8 HKSO4 + 4 I2 + 4 H2O + H2S
AgNO3(aq) + NaCl(aq) = AgCl(s) + NaNO3(aq) =>
AgNO3(aq) + NaCl(aq) = AgCl(s) + NaNO3(aq)
HBr + NH4 = NH4Br + H2 =>
2 HBr + 2 NH4 = 2 NH4Br + H2
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3 =>
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3 =>
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3
Sn(s) + CuSO4(aq) = Cu(s) + Sn2(SO4)4(aq) =>
2 Sn(s) + 4 CuSO4(aq) = 4 Cu(s) + Sn2(SO4)4(aq)
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3 =>
[Al(OH)4]{-} + NH4{+} = NH3 + H2O + Al(OH)3
NaHCO3 + HCl = NaHCl2 + H2CO3 =>
NaHCO3 + 2 HCl = NaHCl2 + H2CO3
FeCl2Hg(NO3)2 = Fe(NO3)2HgCl2 =>
FeCl2Hg(NO3)2 = Fe(NO3)2HgCl2
FeCl3 + CoCl2 = FeCl2 + CoCl3 =>
FeCl3 + CoCl2 = FeCl2 + CoCl3
C2H4 + MnO4{2-} + H{+} = CO2 + Mn{2+} + H2O =>
C2H4 + 3 MnO4{2-} + 12 H{+} = 2 CO2 + 3 Mn{2+} + 8 H2O
Ca(ClO)2 + NaI + HCl = I2 + CaCl2 + NaCl + H2O =>
Ca(ClO)2 + 4 NaI + 4 HCl = 2 I2 + CaCl2 + 4 NaCl + 2 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/19/23
Equations balanced on 12/19/22
Geef ons feedback over uw ervaring met de chemische formule balancer.