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Chemical Equations Balanced on 03/15/08

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KI + Cl2 = KCl + I2 =>
2 KI + Cl2 = 2 KCl + I2

Al + S = Al2S3 =>
2 Al + 3 S = Al2S3

KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2

KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2

C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

(NH4)2CO3 = NH3 + H2O + CO2 =>
(NH4)2CO3 = 2 NH3 + H2O + CO2

MgCO3 = MgO + CO2 =>
MgCO3 = MgO + CO2

NH4OH + H2SO4 = (NH4)2SO4 + H2O =>
2 NH4OH + H2SO4 = (NH4)2SO4 + 2 H2O

I2O5 + CO = I2 + CO2 =>
I2O5 + 5 CO = I2 + 5 CO2

K + O2 = KO =>
2 K + O2 = 2 KO

Mg + SO4 = MgSO4 =>
Mg + SO4 = MgSO4

C2H2 + O2 = CO2 + H2O =>
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

Ni3(PO4)2 + H2SO4 = NiSO4 + H3PO4 =>
Ni3(PO4)2 + 3 H2SO4 = 3 NiSO4 + 2 H3PO4

NH4OH + H2SO4 = (NH4)2SO4 + H2O =>
2 NH4OH + H2SO4 = (NH4)2SO4 + 2 H2O

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + H2O =>
2 H3PO4 + 3 Ca(OH)2 = Ca3(PO4)2 + 6 H2O

NH3 + CuO = Cu + H2O + N2 =>
2 NH3 + 3 CuO = 3 Cu + 3 H2O + N2

NH3 + CuO = Cu + H2O + N2 =>
2 NH3 + 3 CuO = 3 Cu + 3 H2O + N2

H3PO4 + NaOH = Na3PO4 + H2O =>
H3PO4 + 3 NaOH = Na3PO4 + 3 H2O

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

HS + O2 = H2O + SO =>
4 HS + 3 O2 = 2 H2O + 4 SO

HS + O2 = H2O + SO2 =>
4 HS + 5 O2 = 2 H2O + 4 SO2

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

CaO + HCl = CaOHCl =>
CaO + HCl = CaOHCl

SO2 + PCl5 = SOCl2 + POCl3 =>
SO2 + PCl5 = SOCl2 + POCl3

AlCl3 + Pb(NO3)2 = Al(NO3) + Cl2 + Pb =>
2 AlCl3 + Pb(NO3)2 = 2 Al(NO3) + 3 Cl2 + Pb

Pb + CuSO4 = PbSO4 + Cu =>
Pb + CuSO4 = PbSO4 + Cu

Al2O3 + HNO3 = Al(NO3)3 + H2O =>
Al2O3 + 6 HNO3 = 2 Al(NO3)3 + 3 H2O

Al + HBr = AlBr + H =>
Al + HBr = AlBr + H

CO + O2 = CO2 =>
2 CO + O2 = 2 CO2

Al + HBr = AlBr3 + H2 =>
2 Al + 6 HBr = 2 AlBr3 + 3 H2

H2SO4 + KOH = K2SO4 + H2O =>
H2SO4 + 2 KOH = K2SO4 + 2 H2O

SO2 + O2 = SO3 =>
2 SO2 + O2 = 2 SO3

Fe + O2 = Fe3O4 =>
3 Fe + 2 O2 = Fe3O4

H2O = H2 + O2 =>
2 H2O = 2 H2 + O2

Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O

Fe2O3 + C = Fe + CO2 =>
2 Fe2O3 + 3 C = 4 Fe + 3 CO2

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Balance equation of any chemical reaction online for free
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Equations balanced on 03/08/08
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