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Chemische vergelijkingen in evenwicht op12/12/24

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Breng de vergelijking van een chemische reactie in evenwicht
Au + H2O = Au2O + H =>
2 Au + H2O = Au2O + 2 H

CCl3COOH + H2O = CCl3COO + H3O =>
CCl3COOH + H2O = CCl3COO + H3O

NaNO3 + H2 = NH3 + NaOH + H2O =>
NaNO3 + 4 H2 = NH3 + NaOH + 2 H2O

C4H10S2 + O2(g) = CO2(g) + H2O(g) + SO2(g) =>
2 C4H10S2 + 17 O2(g) = 8 CO2(g) + 10 H2O(g) + 4 SO2(g)

HClO4 + Ba(NO3)2 = Ba(ClO4)2 + HNO3 =>
2 HClO4 + Ba(NO3)2 = Ba(ClO4)2 + 2 HNO3

Y2(SO4)3 + NaOH = Y(OH)3 + Na2SO4 =>
Y2(SO4)3 + 6 NaOH = 2 Y(OH)3 + 3 Na2SO4

FeI3 + Pb(NO3)2 = Fe(NO3)3 + PbI2 =>
2 FeI3 + 3 Pb(NO3)2 = 2 Fe(NO3)3 + 3 PbI2

Na4Fe(CN)6 + Cl2 = Na3Fe(CN)6 + NaCl =>
2 Na4Fe(CN)6 + Cl2 = 2 Na3Fe(CN)6 + 2 NaCl

CuCl2 + Cu + HCl = HCuCl2 =>
CuCl2 + Cu + 2 HCl = 2 HCuCl2

C8H8 + Br2 = C8H8Br2 =>
C8H8 + Br2 = C8H8Br2

FePO4 + HCl = H3PO4 + FeCl3 =>
FePO4 + 3 HCl = H3PO4 + FeCl3

CUO + C2 = CU + CO =>
2 CUO + C2 = 2 CU + 2 CO

HCl + CaMg(CO3)2 = CaCl2 + MgCl2 + CO2 + H2O =>
4 HCl + CaMg(CO3)2 = CaCl2 + MgCl2 + 2 CO2 + 2 H2O

NaBr(aq) + KIO3(aq) = NaIO3(s) + BrK(s) =>
NaBr(aq) + KIO3(aq) = NaIO3(s) + BrK(s)

PTCl4 = PTCl2 + Cl2 =>
PTCl4 = PTCl2 + Cl2

PO3C4H11 + C(CH3)3NH2 + CCl4 = PO3NC8H20 + C(CH3)3NH3Cl + HCCl3 =>
PO3C4H11 + 2 C(CH3)3NH2 + CCl4 = PO3NC8H20 + C(CH3)3NH3Cl + HCCl3

CaCl2 + N2 = CaN2 + Cl2 =>
CaCl2 + N2 = CaN2 + Cl2

VO2Cl + Zn + HCl = VCl2 + ZnCl2 + H2O =>
2 VO2Cl + 3 Zn + 8 HCl = 2 VCl2 + 3 ZnCl2 + 4 H2O

NaOH + K2(SO4) = NaSO4 + K2OH =>
NaOH + K2(SO4) = NaSO4 + K2OH

HCl(aq) + MnCl2(aq) + NaBiO3(s) = H2O(l) + HMnO4(aq) + BiCl3(aq) + NaCl(aq) =>
16 HCl(aq) + 2 MnCl2(aq) + 5 NaBiO3(s) = 7 H2O(l) + 2 HMnO4(aq) + 5 BiCl3(aq) + 5 NaCl(aq)

HNO3 + C6H12 = CO2 + H2O + N2 =>
36 HNO3 + 5 C6H12 = 30 CO2 + 48 H2O + 18 N2

K2CrO4(aq) + HCl(aq) + BaCl2(aq) = CrO4(g) + KCl + BaH2 =>
2 K2CrO4(aq) + 2 HCl(aq) + BaCl2(aq) = 2 CrO4(g) + 4 KCl + BaH2

CuCl2 + Cu + HCl = HCuCl2 =>
CuCl2 + Cu + 2 HCl = 2 HCuCl2

Pb(s) + HNO3(s) = PbNO3(aq) + H2O(l) + NO2(g) =>
Pb(s) + 2 HNO3(s) = PbNO3(aq) + H2O(l) + NO2(g)

KMnO4 + H2S + HCl = KCl + MnCl3 + S + H2O =>
KMnO4 + 2 H2S + 4 HCl = KCl + MnCl3 + 2 S + 4 H2O

K2O = O2 + K =>
2 K2O = O2 + 4 K

UO2 + HNO3 = UO2(NO3)2 + NO + H2O =>
3 UO2 + 8 HNO3 = 3 UO2(NO3)2 + 2 NO + 4 H2O

H3PO4 + NH4Cl = (NH4)3PO4 + HCl =>
H3PO4 + 3 NH4Cl = (NH4)3PO4 + 3 HCl

Fe + HC2H3O2 = FeH2 + C2H3O2 =>
Fe + 2 HC2H3O2 = FeH2 + 2 C2H3O2

P2 + S2 = P2S5 =>
2 P2 + 5 S2 = 2 P2S5

Hg2{2+} + CO3{2-} = Hg2CO3 =>
Hg2{2+} + CO3{2-} = Hg2CO3

NaCN + Cl2 + NaOH = NaCNO + NaCl + H2O =>
NaCN + Cl2 + 2 NaOH = NaCNO + 2 NaCl + H2O

Li(OH) + CuCl2 = LiCl + Cu(OH)2 =>
2 Li(OH) + CuCl2 = 2 LiCl + Cu(OH)2

Na2S4O6 + KMnO4 + HNO3 = H2SO4 + Na2SO4 + Mn(NO3)2 + H2O + KNO3 =>
5 Na2S4O6 + 14 KMnO4 + 42 HNO3 = 15 H2SO4 + 5 Na2SO4 + 14 Mn(NO3)2 + 6 H2O + 14 KNO3

KOH + CuO = Cu(OH)2 + K2O =>
2 KOH + CuO = Cu(OH)2 + K2O

H2SiO3 + Fe(OH)3 = Fe2(SiO3)3 + H2O =>
3 H2SiO3 + 2 Fe(OH)3 = Fe2(SiO3)3 + 6 H2O

C6H5NH2 + HNO3 = C6H5NO3 + NH3 =>
C6H5NH2 + HNO3 = C6H5NO3 + NH3

BeO + HCl = Be(OH) + Cl =>
BeO + HCl = Be(OH) + Cl

HCOOH + Fe(OH)2 = (HCOO)2Fe + H2O =>
2 HCOOH + Fe(OH)2 = (HCOO)2Fe + 2 H2O

CH3COONH4 + O2 = CO2 + NH3 + H2O =>
CH3COONH4 + 2 O2 = 2 CO2 + NH3 + 2 H2O

KI + MnSO4 + H2O = Mn(OH)2 + K2SO4 + I2 + H2 =>
2 KI + MnSO4 + 2 H2O = Mn(OH)2 + K2SO4 + I2 + H2

Rb2(SO4) + AlBr3 = Al2(SO4)3 + RbBr =>
3 Rb2(SO4) + 2 AlBr3 = Al2(SO4)3 + 6 RbBr

C2H5CHCl2 + NaOH = C2H5CHO + NaCl + H2O =>
C2H5CHCl2 + 2 NaOH = C2H5CHO + 2 NaCl + H2O

Rb2(SO4) + AlBr3 = Al2(SO4)3 + RbBr =>
3 Rb2(SO4) + 2 AlBr3 = Al2(SO4)3 + 6 RbBr

N2(g) + O2(g) + H2O(g) = NH4NO3(s) =>
2 N2(g) + O2(g) + 4 H2O(g) = 2 NH4NO3(s)

K2[PtCl4] + H2O2 = K2[PtCl4(OH)2] =>
K2[PtCl4] + H2O2 = K2[PtCl4(OH)2]

Sc + Co(ClO3)2 = Co + Sc(ClO3)2 =>
Sc + Co(ClO3)2 = Co + Sc(ClO3)2

Fe + NH4CNS + HNO3 = Fe(CNS)3 + NH4NO3 + H2O =>
8 Fe + 24 NH4CNS + 30 HNO3 = 8 Fe(CNS)3 + 27 NH4NO3 + 9 H2O

CaO + HCl = CaCl2 + H2O =>
CaO + 2 HCl = CaCl2 + H2O

Pb(CLO3)2(aq) + NaI(aq) = PbI2(s) + NaCLO3(aq) =>
Pb(CLO3)2(aq) + 2 NaI(aq) = PbI2(s) + 2 NaCLO3(aq)

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Breng de vergelijking van een chemische reactie in evenwicht
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