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Chemische vergelijkingen in evenwicht op11/25/24

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Breng de vergelijking van een chemische reactie in evenwicht
Cu + AuCl2 = CuCl2 + Au =>
Cu + AuCl2 = CuCl2 + Au

KMn4 + MgS = K2S + Mg(Mn4)2 = MnSO4 + Fe2(SO4)3 + K2SO4 + H2O =>
2 KMn4 + MgS = K2S + Mg(Mn4)2

Br + O2 = Br2O3 =>
4 Br + 3 O2 = 2 Br2O3

Fe(NO3)3(aq) + Na3PO4(aq) = FePO4 + NaNO3 =>
Fe(NO3)3(aq) + Na3PO4(aq) = FePO4 + 3 NaNO3

Ni(NH3)6{2+} + (CH3)2C2(NOH)2 = NH4{+} + NH3 + NiC8H14N4O4 =>
Ni(NH3)6{2+} + 2(CH3)2C2(NOH)2 = 2 NH4{+} + 4 NH3 + NiC8H14N4O4

Mg(OH)2(aq) + HI(aq) = MgI2(aq) + H2O(l) =>
Mg(OH)2(aq) + 2 HI(aq) = MgI2(aq) + 2 H2O(l)

NH4OH + Cu2(SO4)3 = (NH4)2SO4 + Cu(OH)3 =>
6 NH4OH + Cu2(SO4)3 = 3(NH4)2SO4 + 2 Cu(OH)3

NH4OH + NH4Cl = NH4 + ClOH =>
NH4OH + NH4Cl = 2 NH4 + ClOH

C2H60 + K2Cr2O7 + H2SO4 = C2H4O2 + Cr2(SO4)2 + K2S04 + H2O =>
17 C2H60 + 30 K2Cr2O7 + 180 H2SO4 = 17 C2H4O2 + 30 Cr2(SO4)2 + 30 K2S04 + 656 H2O

MgCl2 + LiC2H5 = C2H5MgCl + LiCl =>
MgCl2 + LiC2H5 = C2H5MgCl + LiCl

C18H38(s) + O2 = CO2 + H2O =>
2 C18H38(s) + 55 O2 = 36 CO2 + 38 H2O

C2H6S2 + O2 = CO2 + H2O + S =>
2 C2H6S2 + 7 O2 = 4 CO2 + 6 H2O + 4 S

Fe(HCO3)2 = FeCO3 + H2CO3 =>
Fe(HCO3)2 = FeCO3 + H2CO3

C6H5Cl + AgNO3 = C6H5NO3 + AgCl =>
C6H5Cl + AgNO3 = C6H5NO3 + AgCl

C3H6O + I2 + NaOH = CHI3 + CO2HNa + H2ONaI =>
C3H6O + 5 I2 + 5 NaOH = 2 CHI3 + CO2HNa + 4 H2ONaI

VO2 + HNO3 = VO2(NO3)2 + NO + H2O =>
3 VO2 + 8 HNO3 = 3 VO2(NO3)2 + 2 NO + 4 H2O

Pb + CO2 = PbCO2 =>
Pb + CO2 = PbCO2

NaOH + H3PO4 = Na3PO4 + H2O =>
3 NaOH + H3PO4 = Na3PO4 + 3 H2O

NaNH2(s) + NaNO3(s) = NaN3(s) + NaOH(s) + NH3(g) =>
3 NaNH2(s) + NaNO3(s) = NaN3(s) + 3 NaOH(s) + NH3(g)

As2S5 + NO3{-} + H2O = AsO4{-3} + SO4{-2} + NO + H{+} =>
3 As2S5 + 40 NO3{-} + 4 H2O = 6 AsO4{-3} + 15 SO4{-2} + 40 NO + 8 H{+}

NaH(SO3) = Na2(SO3) + SO2 + H2O =>
2 NaH(SO3) = Na2(SO3) + SO2 + H2O

Fe(NH4)2(SO4)2*6H2O + H2C2O4 = FeC2O4*2H2O + (NH4)2SO4 + H2SO4 + H2O =>
Fe(NH4)2(SO4)2*6H2O + H2C2O4 = FeC2O4*2H2O + (NH4)2SO4 + H2SO4 + 4 H2O

Na3[Cr(OH)6] + NaOH + PbO2 = Na2CrO4 + H2O + Na2[Pb(OH)4] =>
2 Na3[Cr(OH)6] + 4 NaOH + 3 PbO2 = 2 Na2CrO4 + 2 H2O + 3 Na2[Pb(OH)4]

C8H10N4O2 + H2O = HC8H10N4O2 + OH =>
C8H10N4O2 + H2O = HC8H10N4O2 + OH

AgCl + NaOH + C6H12O6 = Ag + C6H11O7Na + NaCl + H2O =>
2 AgCl + 3 NaOH + C6H12O6 = 2 Ag + C6H11O7Na + 2 NaCl + 2 H2O

C2H3OCI + O2 = CO2 + H2O + CI2 =>
4 C2H3OCI + 11 O2 = 10 CO2 + 6 H2O + 2 CI2

NH3 + NH4Cl = NH4 + NCl =>
4 NH3 + NH4Cl = 4 NH4 + NCl

Cr2O72{-} + CH3CH2OH + H{+} = Cr3{+} + CH3CHO + H2O =>
6 Cr2O72{-} + 427 CH3CH2OH + 10 H{+} = 4 Cr3{+} + 427 CH3CHO + 432 H2O

CH3NH3Cl + H2O = CH3NH2 + Cl + H3O =>
CH3NH3Cl + H2O = CH3NH2 + Cl + H3O

Fe2O3 + HF = FeF2 + H2O + O2 =>
2 Fe2O3 + 8 HF = 4 FeF2 + 4 H2O + O2

MgSO4 + KI = MgI2 + K2SO4 =>
MgSO4 + 2 KI = MgI2 + K2SO4

KOH + Ga(OH)3 = K[Ga(OH)4] =>
KOH + Ga(OH)3 = K[Ga(OH)4]

H2(CO3) + Fe(OH)3 = H2O + Fe2(CO3)3 =>
3 H2(CO3) + 2 Fe(OH)3 = 6 H2O + Fe2(CO3)3

C6H6O = C + H2 + O2 =>
2 C6H6O = 12 C + 6 H2 + O2

KMnO4 + Hg + H2SO4 = MnSO4 + Hg2SO4 + K2SO4 + H2O =>
2 KMnO4 + 10 Hg + 8 H2SO4 = 2 MnSO4 + 5 Hg2SO4 + K2SO4 + 8 H2O

Pb + K2CrO4 = PbCrO4 + K =>
Pb + K2CrO4 = PbCrO4 + 2 K

PbO2 + Fe + H2O = Fe(OH)3 + Pb(OH)2 =>
3 PbO2 + 2 Fe + 6 H2O = 2 Fe(OH)3 + 3 Pb(OH)2

(NH4)2C2O4 = NH4 + C2O4 =>
(NH4)2C2O4 = 2 NH4 + C2O4

N2H8PtCl6 = Pt + NH4Cl + N2 + HCl =>
3 N2H8PtCl6 = 3 Pt + 2 NH4Cl + 2 N2 + 16 HCl

K2CrO4 + H2S = Cr(OH)3 + S + KHS + H2O =>
2 K2CrO4 + 7 H2S = 2 Cr(OH)3 + 3 S + 4 KHS + 2 H2O

MnO4 + ClO2 = MnO2 + ClO4 =>
MnO4 + ClO2 = MnO2 + ClO4

H3PO4 + KI = H3I + KPO4 =>
H3PO4 + KI = H3I + KPO4

CuC2H3O2 + (NH4)2S = Cu2S + (NH4)C2H3O2 =>
2 CuC2H3O2 + (NH4)2S = Cu2S + 2(NH4)C2H3O2

Fe(s) + F(g) = Fe3F(s) =>
3 Fe(s) + F(g) = Fe3F(s)

C4H11NO2 + O2 = CO2 + H2O + HNO3 =>
C4H11NO2 + 7 O2 = 4 CO2 + 5 H2O + HNO3

FeCl3(aq) + LiOH(aq) = Fe(OH)3 + LiCl =>
FeCl3(aq) + 3 LiOH(aq) = Fe(OH)3 + 3 LiCl

NaHO + Cl2 = NaCl + NaClO + H2O =>
2 NaHO + Cl2 = NaCl + NaClO + H2O

Hg = Hg2{2+} + e =>
2 Hg = Hg2{2+} + 2e

SnO2 + S + Na2CO3 = Na2SnS2 + SO2 + CO2 =>
2 SnO2 + 7 S + 2 Na2CO3 = 2 Na2SnS2 + 3 SO2 + 2 CO2

C2H3OAr + Cl2 + NaOH = CO2NaAr + CHCl3 + NaCl + H2O =>
C2H3OAr + 3 Cl2 + 4 NaOH = CO2NaAr + CHCl3 + 3 NaCl + 3 H2O

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Breng de vergelijking van een chemische reactie in evenwicht
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