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Chemical Equations Balanced on 06/15/19

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Balance equation of any chemical reaction online for free
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CO + I2O5 = CO2 + I2 =>
5 CO + I2O5 = 5 CO2 + I2

CuS + HNO3 = Cu(NO3)2 + S + NO + H2O =>
3 CuS + 8 HNO3 = 3 Cu(NO3)2 + 3 S + 2 NO + 4 H2O

Pb(NO3)2 + KI = PbI2 + KNO3 =>
Pb(NO3)2 + 2 KI = PbI2 + 2 KNO3

HCl + AgC2H3O2 = AgCl + HC2H3O2 =>
HCl + AgC2H3O2 = AgCl + HC2H3O2

K2SO4 + Ba(NO3)2 = KNO3 + BaSO4 =>
K2SO4 + Ba(NO3)2 = 2 KNO3 + BaSO4

Sn2Cl2 + HNO3 + HCl = SnCl4 + N2 + H2O =>
5 Sn2Cl2 + 6 HNO3 + 30 HCl = 10 SnCl4 + 3 N2 + 18 H2O

SnCl2 + HNO3 + HCl = SnCl4 + N2 + H2O =>
5 SnCl2 + 2 HNO3 + 10 HCl = 5 SnCl4 + N2 + 6 H2O

Ca5F(PO4)3 + H2SO4 = Ca(H2PO4)2 + CaSO4 + HF =>
2 Ca5F(PO4)3 + 7 H2SO4 = 3 Ca(H2PO4)2 + 7 CaSO4 + 2 HF

Fe + H2O = Fe3O4 + H2 =>
3 Fe + 4 H2O = Fe3O4 + 4 H2

CaO + CO2 = CaCO3 =>
CaO + CO2 = CaCO3

SnCl2 + HNO3 + HCl = SnCl4 + N2O + H2O =>
4 SnCl2 + 2 HNO3 + 8 HCl = 4 SnCl4 + N2O + 5 H2O

NaHCO3 + HCl = NaCl + CO2 + H2O =>
NaHCO3 + HCl = NaCl + CO2 + H2O

CuCl2*5H2O = CuCl2 + H2O =>
CuCl2*5H2O = CuCl2 + 5 H2O

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

FeCl3 + H2SO4 = Fe2(SO4)3 + HCl =>
2 FeCl3 + 3 H2SO4 = Fe2(SO4)3 + 6 HCl

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

Zn + PbNO32 = ZnNO32 + Pb =>
Zn + PbNO32 = ZnNO32 + Pb

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

MnO2 + HCl = MnCl2 + Cl2 + H2O =>
MnO2 + 4 HCl = MnCl2 + Cl2 + 2 H2O

Li2SO4 + Na3PO4 = Na2SO4 + Li3PO4 =>
3 Li2SO4 + 2 Na3PO4 = 3 Na2SO4 + 2 Li3PO4

CuCl + AgNO3 = AgCu + ClNO3 =>
CuCl + AgNO3 = AgCu + ClNO3

(CH3)2NNH2 + N2O4 = N2 + H2O + CO2 =>
(CH3)2NNH2 + 2 N2O4 = 3 N2 + 4 H2O + 2 CO2

C3H8O + O2 = CO2 + H2O =>
2 C3H8O + 9 O2 = 6 CO2 + 8 H2O

NH + O2 = NO + H2O =>
4 NH + 3 O2 = 4 NO + 2 H2O

Cu + H2SO4 = CuSO4 + H2O + SO2 =>
Cu + 2 H2SO4 = CuSO4 + 2 H2O + SO2

HClO3 + Ba(OH)2 = HClO4 + Ba + H20 =>
20 HClO3 + 10 Ba(OH)2 = 20 HClO4 + 10 Ba + H20

(CH3)2NNH2 + N2O4 = N2 + H2O + CO2 =>
(CH3)2NNH2 + 2 N2O4 = 3 N2 + 4 H2O + 2 CO2

HClO3 + Ba(OH)2 = HClO4 + Ba + H2O =>
HClO3 + Ba(OH)2 = HClO4 + Ba + H2O

KCl + Sn(CrO4)2 = K2(CrO4) + SnCl4 =>
4 KCl + Sn(CrO4)2 = 2 K2(CrO4) + SnCl4

HClO3 + Ba(OH)2 = HClO4 + Ba + H2O =>
HClO3 + Ba(OH)2 = HClO4 + Ba + H2O

HClO3 + Ba(OH)2 = HClO4 + Ba + H2O =>
HClO3 + Ba(OH)2 = HClO4 + Ba + H2O

HClO3 + Ba(OH)2 = HClO4 + Ba + H2O =>
HClO3 + Ba(OH)2 = HClO4 + Ba + H2O

Na + HCl = H2 + NaCl =>
2 Na + 2 HCl = H2 + 2 NaCl

HClO3 + Ba(OH)2 = HClO4 + Ba + H2O =>
HClO3 + Ba(OH)2 = HClO4 + Ba + H2O

HClO3 + Ba(OH)2 = HClO4 + Ba + H2O =>
HClO3 + Ba(OH)2 = HClO4 + Ba + H2O

C12H22O11 + H20 = C2H5OH + CO2 =>
15 C12H22O11 + 3 H20 = 65 C2H5OH + 50 CO2

C12H22O11 + H20 = C2H5OH + CO2 =>
15 C12H22O11 + 3 H20 = 65 C2H5OH + 50 CO2

SnCl2 + HNO3 + HCl = SnCl4 + N2O + H2O =>
4 SnCl2 + 2 HNO3 + 8 HCl = 4 SnCl4 + N2O + 5 H2O

HClO3 + Ba(OH)2 = HClO4 + Ba + H2O =>
HClO3 + Ba(OH)2 = HClO4 + Ba + H2O

Ag2CO3 + BaF2 = BaCO3 + AgF =>
Ag2CO3 + BaF2 = BaCO3 + 2 AgF

Sb + Cl2 = SbCl3 =>
2 Sb + 3 Cl2 = 2 SbCl3

(CH3)2NNH2 + N2O4 = CO2 + H20 + N2 =>
5 (CH3)2NNH2 + 5 N2O4 = 10 CO2 + 2 H20 + 10 N2

Al + HCl = H2 + AlCl3 =>
2 Al + 6 HCl = 3 H2 + 2 AlCl3

CuSO4 + Al = Al2(SO4)3 + Cu =>
3 CuSO4 + 2 Al = Al2(SO4)3 + 3 Cu

NaOH + H2SO4 = Na2SO4 + HOH =>
2 NaOH + H2SO4 = Na2SO4 + 2 HOH

(CH3)2NNH2 + N2O4 = CO2 + H20 + N2 =>
5 (CH3)2NNH2 + 5 N2O4 = 10 CO2 + 2 H20 + 10 N2

C12H22O11 + H20 = C2H5OH + HCO2 =>
30 C12H22O11 + 11 H20 = 130 C2H5OH + 100 HCO2

NaOH + H2SO4 = Na2SO4 + H2O =>
2 NaOH + H2SO4 = Na2SO4 + 2 H2O

C5H12 + O2 = CO2 + H2O =>
C5H12 + 8 O2 = 5 CO2 + 6 H2O

NaCl + AgNO3 = NaNO3 + AgCl =>
NaCl + AgNO3 = NaNO3 + AgCl

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Balance equation of any chemical reaction online for free
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Equations balanced on 06/08/19
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Equations balanced on 06/15/18
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